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zvonat [6]
3 years ago
7

Why are metals sometimes added to gold?

Chemistry
2 answers:
serious [3.7K]3 years ago
7 0
To make it softer and more malleable
victus00 [196]3 years ago
7 0

Answer:

Because solo gold isn't strong material. But with admixture it's stronger.

Explanation:

In order for the mixture of gold and added metals to become hard and suitable for processing.

Explanation: Gold is precious metal, it has a great value, and it used to serve as a means of payment, but also proof of wealth, status and power. Gold as such is soft, and in order to improve hardness it is mixed with another metal, such as nickel, copper, palladium, zinc, etc. For example, white gold is obtained with a mixture of pure gold and nickel, which gives the mixture a white color, and is sufficiently tough suitable for making rings. Based on the composition of the mixture that is the percentage of gold in the mixture, the number of karats is determined, which also means the value of gold itself. For example, the 999 gold has 99.9% of the gold in the mixture, which means 24 K (karats), and represents the so-called mixture with the most valuable percentage of gold, or the purest of which can be purchased.

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Balance the following chemical equations.
Paul [167]
A)Cu2O(s) + C(s) ———> 2Cu(s)+ CO(g)

B)H2(g) +Cl2(g)———> 2HCl(g)
8 0
2 years ago
How many grams of aluminum are required to produce 8.70 moles of aluminum chloride
Serggg [28]

Answer:

1160.058g

Explanation:

8.70*133.34=1160.058g

4 0
3 years ago
List 4 physical properties of each of the following:
OLEGan [10]
<span>Copper wire - Tensile strength. Coefficient of thermal expansion, Thermal conductivity, Corrosion resistance.

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Glass of Milk - white color, smell, taste and volume

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4 0
3 years ago
in the reaction C5H8 ____02--8H20, what coefficient should be placed in frount of 02 to balance the reaction?
Gekata [30.6K]
5CO2 should be in the blank spot.

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7 0
3 years ago
When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H
algol [13]

Answer: The empirical formula is CH_2 and molecular formula is C_4H_8

Explanation:

We are given:

Mass of CO_2 = 18.95 g

Mass of H_2O= 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =\frac{2}{18}\times 7.759=0.862g of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

Hence the empirical formula is CH_2.

The empirical weight of CH_2 = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4

The molecular formula will be=4\times CH_2=C_4H_8

6 0
3 years ago
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