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2 years ago

The visible part of the spectrum of light is where you find which of the following?

Physics

2 answers:

Marina CMI [18]2 years ago

8 0

C.) All colors .......

Nimfa-mama [501]2 years ago

4 0

The correct answer to the question is- C) All colors i.e the visible part of electromagnetic spectrum of light contains all colors.

EXPLANATION:

The electromagnetic spectrum contains various electromagnetic radiations starting from gamma rays to radio wave.

The electromagnetic waves whose wavelength lie between 350 nano metre to 700 nano metre are visible to human eye. This region of electromagnetic spectrum is called visible light.

The visible light contains white light with its constituent seven colors known as violet, indigo, blue, green, yellow, orange and red.

There are various other colors which are produced due to the intermixing of colors. These colors will also correspond to visible part of the electromagnetic spectrum.

Hence, the correct answer to the question is that it contains all colors.

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What two physical processes balance each other to create the condition known as gravitational equilibrium in stars?

dusya [7]

Answer:

gravitational force and outward pressure

Explanation:

The stars are very massive stellar objects, so they have a strong gravitational force, which drives the star to contract itself, but also in stars there are nuclear reactions such as fusion of hydrogen and other elements, that releases energy and creates a pressure from the center to the star exterior, an outward pressure that goes against the gravitational force. So when a star is stable these two forces exist in equilibrium or in balance, in which the star does not collapse by gravity or disintegrate by its outward pressure.

3 0

3 years ago

What is the mass of the other block?

xeze [42]

Let us consider the tension produced on both the sides of the rope is T.

We have been given that the rope is mass less and the rope is passing through a pulley which is stationary.

$Let\ m_{1} and\ m_{2}\ are\ the\ masses\ of\ two\ blocks$

$Let\ m_{1}\ is\ moving\ in\ vertical\ upward\ direction\ while\ m_{2}\ is\ in\ downward\ \ direction$

$Hence\ m_{2} =4.5\ kg$

The body is moving downward with an acceleration of $\frac{3}{4} g$

As the rope is the same one which is passing over a mass less pulley and connected by two masses,hence, acceleration of each block will be the same in magnitude.

$For\ body\ m_{1}$

Here the tension is acting in vertical upward direction and the weight is acting in vertical downward direction. Here,the body is moving in vertical upward direction. Hence, the net force acting on it is-

$T-m_{1} g=m_{1}a$ [1]

$For\ body\ m_{2}$

Here the tension is acting in vertical upward direction while weight is in vertical downward direction. The body is moving in downward direction. Hence the net force acting on it will be-

$m_{2} g-T=m_{2} a$ [2]

Combing 1 and 2 we get-

$T-m_{1}g=m_{1}a$

$m_{2} g-T=m_{2} a$

-------------------------------------------------

$[m_{2} -m_{1} ]g=a[m_{1}+ m_{2}]$

$[4.5-m_{1}]g =\frac{3}{4}g[4.5+ m_{1}]$

$4[4.5-m_{1}] =3[4.5+m_{1} ]$

$7m_{1} =4.5 kg$

$m_{1} = 0.64286 kg$ [ans]

4 0

2 years ago

A block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp

GuDViN [60]

The work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is a block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp with respect to the horizontal is θ = 23.5° and the length of the ramp is l = 14.1 m.

From the Newton's law of motion,

ma =F-mg sinθ =0

So, the force F = mg sinθ

Plug the values, we get

F = 620N x sin 23.5°

F = 247.224 N

Work done by motor is W= F x d

The force is equal to the weight F = mg

So, W = 247.224 x 14.1

W = 3.486 kJ

Thus, the work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.

Learn more about Work done

brainly.com/question/13662169

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7 0

1 year ago

On an icy winter day, the coefficient of friction between the tires of a car and a roadway is reduced to 1/4 its value on a dry

Naddik [55]

Answer:

50%

Explanation:

For the particular case we assume that the centripetal force is equal to the frictional force. Starting from this, we realize that while the car takes a curve, which allows it to not leave the track, it is the friction force that adheres it to the floor, in this way,

$F_c = F_f$