Addition of 2vector gives you 1large vector quantity
The wavelength of the wave is 0.055 m
Explanation:
The relationship between speed, frequency and wavelength of a wave is given by the wave equation:

where
v is the speed
f is the frequency
is the wavelength
For the sound wave in this problem we have
v = 340 m/s is the speed
f = 6,191 Hz is the frequency
Solving for
, we find the wavelength:

Learn more about waves and wavelength:
brainly.com/question/5354733
brainly.com/question/9077368
#LearnwithBrainly
Answer:
0.0257259766982 m
Explanation:
= Atmospheric pressure = 101325 Pa
= Initial diameter = 1.5 cm
= Final diameter
= Density of water = 1000 kg/m³
h = Depth = 40 m
The pressure is

From ideal gas law we have

The diameter of the bubble is 0.0257259766982 m
Answer:
As the tines of the tuning fork vibrate at their own natural frequency, they created sound waves that impinge upon the opening of the resonance tube. These impinging sound waves produced by the tuning fork force air inside of the resonance tube to vibrate at the same frequency.