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taurus [48]
4 years ago
13

A batter swings at a baseball. The action force is the bat hitting the ball with a force of 5N. What is the reaction force?

Physics
2 answers:
nlexa [21]4 years ago
7 0

Answer:

The ball hitting the bat.

Explanation:

It is given that, a batter swings at a baseball. When the ball is being hitted by the bat, the action force acting on it is 5 N. Let R is the reaction force. It is equal to the action force but it acts in the opposite direction as per Newton's third law of motion.

The action and reaction forces acts on two different objects. Here, if the action force is " bat hitting the ball" then the reaction force will be "the ball hitting the bat" with a force of -5 N.

Hence, the correct option is (d) "the ball hitting the bat".

omeli [17]4 years ago
6 0
The ball hitting the bat
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3 years ago
How do we solve questions C and D? I already did A and B and I am confused on how to continue
aleksandrvk [35]

(a) The work done in moving the unit charge from point C to A is 7.62 x 10⁻³ J.

(b) The work done in moving the unit charge from point D to B is 7.62 x 10⁻³ J.

<h3>Work done in moving the charge from C to A</h3>

W = Fd

W = Kq²/d

  • from 0 origin to C, d = √(5² + 5²) = 7.07 m
  • from 0 origin to A, d = 5 m

W(C to A) = W(0 to C) + W(0 to A)

W(C \ to \ A) = - \frac{Kq^2}{7.07} + \frac{Kq^2}{5} \\\\ W(C \ to \ A)  = 0.0586 \ Kq^2\\\\W(C \ to \ A)  = 0.0586 \times 9 \times 10^9 \times (3.8\times 10^{-6})^2\\\\W(C \ to \ A)  = 7.62 \times 10^{-3} \ J

<h3>Work done in moving the charge from D to B</h3>
  • from 0 origin to D, d = √(5² + 5²) = 7.07 m
  • from 0 origin to B, d = 5 m

W(D to B) = W(0 to D) + W(0 to B)

W(D to B) = 7.62 x 10⁻³ J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

8 0
2 years ago
Which option identifies the best technique to employ in the following scenario?
ollegr [7]
Answer: Urban Green House
8 0
2 years ago
Photons with wavelength 1 pm are incident on electrons. What is the frequency of the Compton-scattered photons at an angle of 60
natali 33 [55]

Answer:

f = 1.354*10^{20} Hz

Explanation:

By conservation of linear momentum, wavelength shift due to collision of photon to electron is given by following formula

\lambda ^{'}-\lambda =\frac{h}{m_{o}c}(1-cos\theta )

where h is plank constant = 6.626*10^{-34}

c = speed of light = 3*10^{8} m/s

scattered angle  =  60 degree

m = rest mass of electron  = 9*10^{-31}

\lambda ^{'}=10^{-12} +\frac{6.626*10^{-34}}{9*10^{-31}*3*10^{8}}(1-cos60^{o} )

\lambda ^{'}= 2.215 pm

we know that 1 pm = 10^{-12}m

f = \frac{c}{\lambda ^{'}}

f = \frac{3*10^{8}}{2.215 *10^{-12}} = 1.354*10^{20} Hz

f = 1.354*10^{20} Hz

4 0
3 years ago
Can I get any help?
Pavel [41]
Try B, it seems correct. I’m very sorry if i’m incorrect.
7 0
3 years ago
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