Help me with these questions.

How many protons are in an ion with 54 electron and -1 charge?

lora16 [44]

The correct answer is 53.

It would be neutral if they were both at 53, however, since there's 54 electron, then it becomes negatively electrified and becomes -1. You just delete one number from it and you'll see that it's 53.

8 0

3 years ago

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How does the phosphorous cycle differ from the nitrogen cycle and the carbon cycle?

Ahat [919]

A good way to answer this would be to think about what the major sinks of each resource are. For example phosphorus is mainly pooled in rocks and is released when rocks are weathered and then cycles with the death and decay of plants (etc.) that take it up.

It doesn't occur like this for the nitrogen and carbon cycles - what are their major sinks?

I've attached a pdf which outlines the cycles pretty well :)

Download pdf

5 0

3 years ago

Suppose a 500.mL flask is filled with 1.9mol of NO3 and 1.6mol of NO. The following reaction becomes possible: NO3gNOg 2NO2g The

never [62]

There is an error in the first sentence of the question; the right format is:

Suppose a 500.mL flask is filled with 1.9mol of NO3 and 1.6mol of NO2.

It should be NO2 and not NO.

Answer:

The equilibrium molarity of NO = 0.21695 m

Explanation:

Given that :

the volume = 500 mL = 0.500 m

number of moles of $NO_3 = 1.9 \ mol$

number of moles of $NO_2 = 1.6 \ mol$

Then we can calculate for their respectively concentrations as :

$[NO_3] = \frac{number \ of \ moles}{volume}$

$[NO_3] = \frac{1.9}{0.500}$

$[NO_3] = 3.8 \ M$

$[NO_2] = \frac{number \ of \ moles}{volume}$

$[NO_2] = \frac{}{} \frac{1.6}{0.500}$

$[NO_2] = 3.2 \ M$

The chemical reaction can be written as:

$NO_3_{(g)} + NO_{(g)} \to 2NO_2_{(g)}$

The ICE table is as follows;

$NO_3_{(g)} + NO_{(g)} \to 2NO_2_{(g)}$

Initial 3.8 - 3.2

Change +x x -2x

Equilibrium 3.8+x +x 3.2 - 2x

$K_c=\frac{[NO_2]^2}{[NO_3][NO]}$

$where \ K_c = 8.33$

$8.33 = \frac{(3.2-2x)^2}{(3.8+2x)x} \\ \\ 8.33 = \frac{(3.2-2x)^2}{(3.8x+2x^2)}$

$8.33(3.8x + 2x^2) = (3.2-2x)^2 \\ \\ 31.654x + 16.66x^2 = (3.2-2x)(3.2-2x) \\ \\ 31.654x + 16.66x^2 = 10.24 - 12.8x +4x^2 \\ \\ 10.24 - 44.454x -12.66 x^2 = 0 \\ \\ 12.66x^2 +44.454x -10.24 = 0$

Using quadratic formula;

$\frac{-b\pm \sqrt{(b)^2-4ac} }{2a}$

= $\frac{-(44.454) + \sqrt{(44.454)^2-4(12.66)(-10.24)} }{2(12.66)} \ \ OR \ \ \frac{-(44.454) - \sqrt{(44.454)^2-4(12.66)(-10.24)} }{2(12.66)}$

= 0.21695 OR -3.7283

Going by the positive value;

x = 0.21695

$[NO_3] = 3.8 +x = 3.8 + 0.21695$

= 4.01695 m

[NO] = x = 0.21695 m

$[NO_2] = 3.2 +x = 3.2 + 0.21695$

= 3.41695 m

3 0

3 years ago

Does a low or a high pressure air mass have a greater atmospheric pressure than the surrounding air masses?

Ghella [55]

Answer:

Hello fellow brainlian! here is the answer that you seek:High pressure areas are usually caused by air masses being cooled, either from below (for instance, the subtropical high pressure zones that form over relatively cool ocean waters to the west of Califormia, Africa, and South America

Explanation:

Have a totally horse-some day!

With love,

-The one and only Alaska

8 0

3 years ago

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Answer this for 100 points.

lukranit [14]

Answer:

A I think

Explanation:

4 0

3 years ago

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