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Rus_ich [418]
3 years ago
9

A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is -1.67 m/s^2. Determine

the time for the feather to fall to the surface of the moon?
Physics
1 answer:
zalisa [80]3 years ago
5 0
<span>We can use a simple equation to find the time for the feather to fall to the surface. y = (1/2) g t^2 y is the height g is the acceleration due to gravity t is the time t^2 = 2y / g t = sqrt{ 2y / g } t = sqrt{ (2) (1.40 m) / (1.67 m/s^2) } t = sqrt { 1.6766 s^2 } t = 1.29 seconds It takes 1.29 seconds for the feather to fall to the surface.</span>
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Answer:

<h3>14.97m/s</h3>

Explanation:

Given

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Required

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Using the equation of motion

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v² = 64+160

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Hence the rider's velocity after the acceleration is 14.97m/s

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Cadences.

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3 years ago
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