Answer:

Step-by-step explanation:
we know that
The equation of the circle in center radius form is equal to

where
(h,k) is the center of the circle
r is the radius of the circle
In this problem we have

substitute


Your answer is D) 9.
This is because the slope of any line in the form y = mx + c is represented by the multiplier of x, which in this case is 9.
I hope this helps!
Answer:

Step-by-step explanation:
If the system contains
atoms, we can arrange
quanta of energy in
ways.

In this case,
.
Therefore,

which means that we can arrange 1 quanta of energy in 2 ways.

In this case,
.
Therefore,

which means that we can arrange 10 quanta of energy in 184 756 ways.

In this case,
.
Therefore, we obtain that the number of ways is

Answer:
I'm gonna assume you mean feet to yards: 640 feet
Step-by-step explanation:
hope this helps
brainliest plzzz
Answer:
$113
Step-by-step explanation:
Since he had $13 and now he is $100 in debt:
First, he withdrew $13 to get $0 in his bank account.
He then withdrew $100 to get -$100 in his bank account.
13 + 100 = 113