Answer;
Molar mass of water is 18.02 g/mol
Explanation;
-Molar mass of a compound is determined by adding the relative atomic mass of each atom present in the compound. Molar mass of one mole of a compound, it is the weight in grams of 6.02 × 1023 atoms or molecules.
-Therefore; to calculate the molar mass of Water (H2O); we first know the RAM of hydrogen and oxygen which are; H=1.01 and O= 16.00
Since there is two atom of hydrogen and one atom of oxygen in water;
Then; the Molar mass of water will be; 2×1.01 + 1 ×16 = 18.02 g/mol
Answer:
10.11 mL
Explanation:
Given that :
Total volume of decolorizer = 500 mL
A common recipe is equal parts 95% ethanol and acetone.
So;
The volume of 95% ethanol in the decolorizer = 500mL/2 = 250 mL
Let represent V(ml) for the 99% of ethanol needed to make 95% of the 250 mL of ethanol;
Therefore:
V(ml) × 0.99 = 250 × 0.95
V(ml) × 0.99 = 237.5
V(ml) = 237.5/0.99
V(ml) = 239.89 mL
Hence; the amount of water to be added to 95% of ethanol = ( 250 - 239.89 )mL = 10.11 mL
Answer: There are 18 electrons accounted for in the noble gas of the shorthand electron configuration. For the outermost electrons, there are 0 electrons in the 4s orbital and 3 electrons in the 3d orbitals.
Explanation:
Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.
The electrons are filled according to Afbau's rule in order of increasing energies and thus the electronic configuration for Manganese with 25 electrons is :
![Mn^{4+}:21:[Ar]3d^3](https://tex.z-dn.net/?f=Mn%5E%7B4%2B%7D%3A21%3A%5BAr%5D3d%5E3)
The nearest noble gas is Argon with 18 electrons.
There are 18 electrons accounted for in the noble gas of the shorthand electron configuration. For the outermost electrons, there are 0 electrons in the 4s orbital and 3 electrons in the 3d orbitals.
Answer:
Percentage Yield = 56.9% (to 3 significant figures)
Explanation:
Firstly you need to calculate the amount of moles of Na used. Moles = Mass/Mr, so moles of Na = 1.72x10^-3/23. This gets you 7.47826087x10^-5 moles.
The mole ratio of Na:Na2O is 2:1 so the moles of Na2O will be the moles of Na divided by 2. This gets you 3.739130435x10^-5 moles.
Mass = Moles x Mr
The Mr of Na2O = 62
Mass = 3.739130435x10^-5 x 62 = 2.31826087x10^-3g
Percentage Yield = (Actual Yield / Theoretical Yield) x 100
Percentage Yield = (1.32x10^-3 / 2.31826087x10^-3) x 100
Percentage Yield = 56.93923481%
Percentage Yield = 56.9% (to 3 significant figures)
It is the s-orbital because the order of electrons is s-block, p-block, d-block, and f-block. The p, d, and I think f as well (not 100% about f though) can each hold 8 more valence electrons in their shells.
