Answer:
The temperature will decrease to 50 K
Explanation:
Step 1: Data given
Temperature = 127 °C = 400 K
Pressure = 2.00 atm
The pressure decreases to 0.25 atm
Volume and number of moles do not change
Step 2: Calculate the new pressure
p1/T1=p2/T2
⇒with p1 = The initial pressure = 2.00 atm
⇒with T1 = The initial temperature = 127 °C = 400 K
⇒with p2 = the new pressure = 0.25 atm
⇒with T2 = the new temperature = TO BE DETERMINED
2.00 atm / 400 K = 0.25 atm / T2
0.005 = 0.25 / T2
T2 = 0.25/0.005
T2 = 50 K
The temperature will decrease to 50 K
Answer:
24.24 g
Explanation:
First we <u>calculate how many moles are there in 300 mL of a 0.234 M solution</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
Converting 300 mL to L ⇒ 300 mL / 1000 = 0.300 L
- 0.234 M = moles / 0.300 L
Then we <u>convert 0.78 moles of NH₄F into grams</u>, using its <em>molar mass</em>:
- 0.78 mol * 31.073 g/mol = 24.24 g
Answer:
B. Evaporation and condensation
Explanation:
Evaporation includes a phase change from liquid to gas. Condensation includes a phase change from gas to liquid. Also, It is the invisible process of evaporation that changes liquid and frozen water into water-vapor gas, which then floats up into the skies to become clouds. Hope this helps!!
Answer:
96,532,000,000,000,000,000,000 ions.
Explanation:
- Assume the highest concentration of HCl in the stomach (160 mmol/L) that is in the canaliculi.
- This means that 1.0 L of the stomach acid contains 0.160 mol.
- Every 1.0 mole of HCl contains Avogadro’s number of molecules (6.022 x 10²³) molecules.
- Every 1.0 molecule of HCl contains 1.0 H⁺ ion.
<u><em>Using cross multiplication:</em></u>
1.0 mole of HCl → 6.022 x 10²³ H⁺ ions.
0.160 mole of HCl → ??? H⁺ ions.
∴ The no. of H⁺ ions in 1 liter of stomach acid = (6.022 x 10²³ H⁺ ions)(0.160 mole of HCl) / (1.0 mole of HCl) = 9.6352 x 10²² ions = 96,532,000,000,000,000,000,000 ions.