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lapo4ka [179]
2 years ago
12

What would happen to your weight if your mass doubled?

Physics
1 answer:
Novosadov [1.4K]2 years ago
3 0

Answer: In turn, your weight would also double.

Explanation:

This is because the perceived weight of an object is directly proportional to its mass, which means that if the mass doubles, then the weight doubles.

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What does balanced and unbalanced forces have to do with newtons laws of motion
Ivahew [28]
Newton's second law of motion involves the effect of force acting on a mass.
It has to be understood that this actually means the combination of any and
all individual forces acting on it, with their individual strengths and directions
all added together.

When all the individual forces acting on an object add up to zero, then the
whole group of forces is said to be 'balanced'.

When all the individual forces acting on an object don't add up to zero, then
the whole group of forces is said to be 'unbalanced'.

Notice that there's no such thing as 'a balanced force' or 'an unbalanced force'.
It's a <u>group</u> of two or more forces that's balanced or unbalanced.



5 0
3 years ago
A series circuit has a current of 3 A. The circuit contains a 12 resistor. What is the voltage of the circuit?
muminat

Answer:

36 volts

If the circuit has a current of 3 amps, and a 12 ohm resistor.

12 x 3 = 36volts

6 0
3 years ago
Read 2 more answers
A car moves at speed v across a bridge made in the shape of a circular arc of radius r. (a) Find an expression for the normal fo
inna [77]

Answer:

(a) FN = m (g - \frac{v^{2} }{r})

(b) vmin = 17.146 m/s

Explanation:

The radius of the arc is

r = 30m

The normal force acting on the car form the highest point is

FN = m (g - \frac{v^{2} }{r})

If the normal force become 0 we have

m (g - \frac{v^{2} }{r}) = 0

or

g - \frac{v^{2} }{r} = 0

This way, when FN = 0, then v = vmin, so

g - \frac{vmin^{2} }{r} = 0

vmin = \sqrt[.]{g*r} = \sqrt[.]{9.8 m/s^{2} * 30m } = 17.146 m/s

4 0
4 years ago
How much power is developed in a car that can pull a 5000 N at a constant speed<br> of 20 m/s?
egoroff_w [7]

Answer:

YAYA MAN

Explanation:

5 0
3 years ago
If you drop a silver dollar off a building and it hits the ground in 10 seconds, how fast was the coin going just before it hit?
Illusion [34]
Objects in free fall, disregarding terminal velocity, accelerate at 9.8(m/s)/s. so for every second it was falling, it gained 9.8m/s in speed. 9.8 * 10 = 98m/s
4 0
3 years ago
Read 2 more answers
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