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dexar [7]
2 years ago
8

How should students prepare to use chemicals in the lab?.

Chemistry
1 answer:
Serggg [28]2 years ago
6 0

Answer:

Become familiar with the chemicals to be used, including exposure or spill hazards.

Locate the spill kits and understand how they are used.

Explanation:

Hope this helped! :)

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10 POINTS!!! Which statement best defines a universal law?
Nadya [2.5K]

Answer: Universal law refers to as legal legitimacy,  where those principles and rules are for governing the country. They are most universal in (AATPB) acceptability, applicability, translation, and philosophical basis. They are also considered to be most legitimate.

So basically the answer is A

They are in effect all the time.

Explanation:

Hopefully this helps you

pls mark brainlest

5 0
3 years ago
Explain a polar molecules and give examples​
ivanzaharov [21]
Ethanol is polar because the oxygen atoms attract electrons because of their higher electronegativity than other atoms in the molecule. Thus the -OH group in ethanol has a slight negative charge. Ammonia (NH3) is polar. Sulfur dioxide (SO2) is polar.
8 0
3 years ago
What is the molar mass of CaCl2?
alekssr [168]
Molar mass of CaCl2 = 40+ ( 35.5 ×2)=110

Mr of Ca(OH)2 = 40+ (16+1)×2 =74

%of Ca = (40÷ 74)×10=...

1 m = 100cm...
1cm = (1÷100) m
So 45.5 cm = 45.5 ×(1÷100) =....

1km = 1000m
1m = 100 cm
1cm =10mm
So 1km = 1000×100×10 mm
Now convert
7 0
3 years ago
What is the molar concentration of hydronium ions in a sample of a soft drink that has a ph of 4?
hammer [34]

[H^{+}] value of soft drink is 0.0001mol/l when given pH is 4.

Given:

pH = 4

Needs to find: [H^{+}]

Formula to find: pH=−log_{10} [H^{+}]

We can put the values of pH in above formula as,

pH=−log_{10} [H^{+}]

4 =−log_{10} [H^{+}]

To calculate hydonium ion concentration, formula is as follows;

[H^{+}] = 10^{-pH}

[H^{+}] = 10^{-4} = 0.0001mol/l

[H^{+}] value of soft drink is 0.0001mol/l

Learn more about pH here:

brainly.com/question/2288405

#SPJ4

6 0
2 years ago
Estimate the heat of neutralization of H3PO4 in kJ/mol given these data: Heat transferred = 2.2 x 102 J Moles of H3PO4 = 1.5 x 1
barxatty [35]
<span>write out the balance equation
3NaOh+H3PO4->Na3PO4+3H2O
You are given everything needed to calculate
q=heat transfer=2.2*10^2,
H3PO4 moles= 1.5*10^-3,
NaOH moles=5.0*10^-3
equation is deltaHneutraliztion=q/Moles of limiting reagent H3PO4 is limiting reagent because lowest moles, and is used up first
Now plug in variables
DeltaH=2.2*10^2(1.5*10^3)= 146.67kj/mole
Notice we had to convert J to kj,</span>
4 0
3 years ago
Read 2 more answers
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