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2 years ago

What is glacier flood?

Physics

2 answers:

posledela2 years ago

3 0

Answer:

A glacial lake outburst flood is a type of outburst flood caused by the failure of a dam containing a glacial lake. An event similar to a GLOF, where a body of water contained by a glacier melts or overflows the glacier, is called a jökulhlaup. The dam can consist of glacier ice or a terminal moraine.

lawyer [7]2 years ago

3 0

Answer:

A Glacial Lake Outburst Flood is a sudden release of water from a lake fed by glacier melt that has formed at the side, in front, within, beneath, or on the surface of a glacier

Explanation: yw

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True or False: There is no object that can travel faster than the speed of light.

Otrada [13]

True no object can travel faster than speed of light

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3 years ago

A net force of 25N causes an object to accelerate at 4m/s^2. what is the mass of the object?

Doss [256]

Answer:

6.25 kg

Explanation:

Fnet=ma

m=Fnet/a

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m=6.25kg

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3 years ago

An airplane accelerates from rest down a runway at 3.20 m/s2 for 32.8 seconds until it lifts off the ground. Determine the dista

vagabundo [1.1K]

Answer:

s=1721.344m ,v=104.96m/s.

Explanation:

using thr equation of motion;

$s=ut+\frac{1}{2}at^{2}$

u=0, plane starts from rest,

$s=\frac{1}{2}at^{2}$

$a=3.2m/s^{2}, t=32.8s \\ s=\frac{1}{2}*3.2*32.8^{2}$

s=1721.344m

v=u+at

v=0 +3.2*32.8

v=104.96m/s

8 0

3 years ago

A flatbed truck is carrying a 20.0 kg crate along a level road. the coefficient of static friction between the crate and the bed

Dahasolnce [82]

<span>3.92 m/s^2 Assuming that the local gravitational acceleration is 9.8 m/s^2, then the maximum acceleration that the truck can have is the coefficient of static friction multiplied by the local gravitational acceleration, so 0.4 * 9.8 m/s^2 = 3.92 m/s^2 If you want the more complicated answer, the normal force that the crate exerts is it's mass times the local gravitational acceleration, so 20.0 kg * 9.8 m/s^2 = 196 kg*m/s^2 = 196 N Multiply by the coefficient of static friction, giving 196 N * 0.4 = 78.4 N So we need to apply 78.4 N of force to start the crate moving. Let's divide by the crate's mass 78.4 N / 20.0 kg = 78.4 kg*m/s^2 / 20.0 kg = 3.92 m/s^2 And you get the same result.</span>

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3 years ago

A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-

Alisiya [41]

First we need to convert the angular speed from rpm to rad/s. Keeping in mind that
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$1 min = 60 s$
the angular speed is
$\omega = 7.18 \frac{rev}{min} \cdot \frac{2 \pi}{60} = 0.75 rad/s$

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
$v= \omega r = (0.75 rad/s)(4.65 m)=3.50 m/s$

3 0

3 years ago

What is glacier flood?​

What is glacier flood?