Describe the trend (pattern) in the numbers of mobile phone owners in the Uk since 1990.
1 answer:
Explanation:
<em><u>SMARTPHONE OWNERSHIP IS GROWING RAPIDLY AROUND THE WORLD, BUT NOT ALWAYS THE SAME.</u></em>
In emerging economies, the use of technology is still more common among the young and the educated
A farmer takes a selfie with a smartphone at a rally in Jaipur, India. (Vishal Bhatnagar/AFP/Getty Images)
A farmer takes a selfie with a smartphone at a rally in Jaipur, India. (Vishal Bhatnagar/AFP/Getty Images)
The chart shows that smartphone ownership in advanced economies is higher than in emerging economies.
Mobile technology has spread rapidly around the world. Today, it is estimated that more than 5 billion people have mobile devices, and more than half of these connections are smartphones. But growth in mobile technology so far has been unequal, either nationwide or within it. People in advanced economies are more likely to have mobile phones - smartphones in particular - and more likely to use the internet and social media than people in emerging economies. For example, a median of 76% across the 18 advanced economies surveyed have a smartphone, compared to a median of only 45% in emerging economies.
Smartphone ownership can vary by country, and even across developed economies. While about nine in ten or more South Koreans, Israelis and the Netherlands own a smartphone, the ownership rate is closer to six in ten in other developed countries such as Poland, Russia and Greece. In emerging economies as well, smartphone ownership rates vary significantly, from a high of 60% in South Africa and Brazil to just around four in ten in Indonesia, Kenya and Nigeria. Among the countries surveyed, ownership was lowest in India, where only 24% reported having a smartphone.
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Answer:
The heat at constant pressure is -3,275.7413 kJ
Explanation:
The combustion equation is 2C₆H₆ (l) + 15O₂ (g) → 12CO₂ (g) + 6H₂O (l)
= (12 - 15)/2 = -3/2
We have;
Where R and T are constant, and ΔU is given we can write the relationship as follows;
Where;
H = The heat at constant pressure
U = The heat at constant volume = -3,272 kJ
= The change in the number of gas molecules per mole
R = The universal gas constant = 8.314 J/(mol·K)
T = The temperature = 300 K
Therefore, we get;
H = -3,272 kJ + (-3/2) mol ×8.314 J/(mol·K) ×300 K) × 1 kJ/(1000 J) = -3,275.7413 kJ
The heat at constant pressure, H = -3,275.7413 kJ.
Answer:
Explanation:
Hello,
In this case, we write the reaction again:
In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:
Next, as lead (II) nitrate and potassium iodide are in a 1:2 molar ratio, 0.04635 mol of lead (II) nitrate will completely react with the following moles of potassium nitrate:
But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:
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