Answer:
Q = 230.36 C
Explanation:
Given
R = 3.54 Ω
t = 30'45" = (30')*(60"/1') + 45" = 1845 s
V = 442 mV = 442*10⁻³V
Q = ?
We can use Ohm's Law in order to get I as follows
V = I*R ⇒ I = V / R
⇒ I = 442*10⁻³V / 3.54 Ω = 0.1248 A
Finally we use the formula
I = Q / t ⇒ Q = I*t = (0.1248 A)(1845 s)
⇒ Q = 230.36 C
What represents acceleration on a velocity time graph is THE SLOPE OF THE GRAPH.
The slope of a velocity time graph represent the acceleration of the object, that is, the value of the slope at a particular time represent the acceleration of the object at that point in time.
<span>The answer is: 30 ft³ ; or, write as: 30 cubic feet .
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Explanation:
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Given:
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Density = 0.4 fish(es) per cubic foot (or, feet);
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or, "Density = 0.4 fish / ft³ ;
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And, given: "12 fish in the tank." ;
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And Density = (value; in this case, "number of fish" / unit volume);
We are given: Density, "D" = 0.4 fish / 1 ft³
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In our case, our volume is in "cubic ft." ; or, "ft³ ;
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We want to find the actual volume of the tank (in "cubic feet"; or, " ft³ ");
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→ (1 ft³ / 0.4 fish) * 12 fish = _____? ft³ ?
→ On the "left-hand side" of the equation; the units of "fish" cancel out to "1"; and we are left with units of "ft³ " ; which is the units for which we wish to solve.
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→ So, so have (1 ft³ * 12) / (0.4) = 12 ft³ / 0.4 = 30 ft³ .
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<span> → The answer is: 30 ft³ ; or, write as: 30 cubic feet .</span>
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When 2 electric charges are place close to each other they experience a force between them. This force may be repulsive or attractive depending on the type of charges involved.
The magnitude of this force depend on the quantity of individual charges and the distance between them.
The force is defined by the <em>Coulomb's law</em> states that: <em>The magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.</em>
The formula for calculating the force between 2 electric charges is ;
F = (kq₁q₂)/d²
Where k is the proportionality constant known as Coulomb's constant,
q₁ and q₂ are the charges and
d is the distance between q₁ and q₂.
Basing on the information given, we can calculate the new weight of the object by the following given:current weight = 20 Ng = 10m/s2
20N/4 = 5N
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