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klemol [59]
3 years ago
9

Gaseous chlorine dioxide (ClO2) is used in bleaching flour and municipal water treatment in

Chemistry
1 answer:
trapecia [35]3 years ago
5 0

Taking into account the ideal gas law, the pressure is 2.52 atm.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas are related by a simple formula called the ideal gas law. This equation relates the three variables if the amount of substance, number of moles n, remains constant. The universal constant of ideal gases R has the same value for all gaseous substances. The numerical value of R will depend on the units in which the other properties are worked.

P×V = n×R×T

In this case, you know:

  • P=?
  • V= 500 L
  • n= 52.1 moles
  • R= 0.082\frac{atmL}{molK}
  • T= 22 C= 295 K (being 0 C=273 K)

Replacing in the ideal gas law:

P×500 L = 52.1 moles ×0.082 \frac{atmL}{molK} ×295 K

Solving:

P= (52.1 moles ×0.082 \frac{atmL}{molK} ×295 K)÷ 500 L

<u><em>P= 2.52 atm</em></u>

Finally, the pressure is 2.52 atm.

Learn more about ideal gas law:

  • brainly.com/question/4147359?referrer=searchResults
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Sound waves are transverse mechanical waves. <br><br> True<br> False
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False

Explanation:

Sound waves are longitudinal mechanical waves.

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A sample of nitrogen gas is at a temperature of 50 c and a pressure of 2 atm. If the volume of the sample remains constant and t
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Answer:

The new temperature of the nitrogen gas is 516.8 K or 243.8 C.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Where P = pressure, T = temperature, K = Constant

You want to study two different states, an initial state and a final state. You have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment. By varying the temperature to a new value T2, then the pressure will change to P2, and the following will be fulfilled:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 2 atm
  • T1= 50 C= 323 K (being 0 C= 273 K)
  • P2= 3.2 atm
  • T2= ?

Replacing:

\frac{2 atm}{323 K} =\frac{3.2 atm}{T2}

Solving:

T2*\frac{2 atm}{323 K} =3.2 atm

T2=3.2 atm*\frac{323 K}{2 atm}

T2= 516.8 K= 243.8 C

<u><em>The new temperature of the nitrogen gas is 516.8 K or 243.8 C.</em></u>

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