Answer : The molecule of ethane present in 64.28 L of ethane gas at STP is, 
molecule.
Solution :
At STP,
22.4 L volume of ethane present in 1 mole of ethane gas
64.28 L volume of ethane present in 
of ethane gas
And, as we know that
1 mole of ethane molecule contains 
molecules of ethane
2.869 moles of ethane molecule contains 
molecules of ethane
Therefore, the molecule of ethane present in 64.28 L of ethane gas at STP is, molecule.
Density can be calculated using the following rule:
density = mass / volume
therefore,
mass = density x volume
From the givens:
we have the density = 1030 kg/m^3 and volume = 1.89 m^3
Substitute in the equation to get the mass as follows:
mass = 1030 x 1.89 = 1.9467 x 10^3 kg
Answer:
B the rides are to the sun
Answer:
Glucose has a chemical formula of:C6H12O6 That means glucose is made of 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms. You will be building one type of sugar called glucose.
B
step-by-step explanation
