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nordsb [41]
2 years ago
12

Number 43 and 44 can you help me plz

Chemistry
1 answer:
velikii [3]2 years ago
7 0

Answer:

43

a) 6.730 x 10^-4

b) 5.0 x 10^4

c) 3.010 x 10^-6  

44

a) 7050. g

b) 40000500. mg

c) 2350.0 mL

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Answer:

Mole fraction of alcohols in liquid phase x_1=0.2727\& x_2=0.7273.

Mole fraction of alcohols in vapor phase y_1=0.1468\& y_2=0.8516.

Explanation:

The total vapor pressure of the solution = p =38.6 Torr

Partial vapor pressure of the  n-propyl alcohol =p^{o}_1=21.0 Torr

Partial vapor pressure of the isopropyl alcohol =p^{o}_2=45.2 Torr

p=x_1\times p^{o}_1+x_2\times p^{o}_2  (Raoult's Law)

p=x_1\times p^{o}_1+(1-x_1)\times p^{o}_2

38.6 Torr=x_1\times 21.0 Torr+(1-x_1)\times 45.2 Torr

x_1=0.2727

x_2=1-0.2727=0.7273

x_1\& x_2 is mole fraction in liquid phase.

Mole fraction of components in vapor phase y_1\& y_2

p_1=y_1\times p (Dalton's law of partial pressure)

y_1=\frac{p_1}{38.6 Torr}=\frac{p^{o}_1\times x_1}{38.6 Torr}

y_1=\frac{21.0 Torr\times 0.2727}{38.6 Torr}=0.1468

y_1=\frac{p_2}{38.6 Torr}=\frac{p^{o}_2\times x_2}{38.6 Torr}

y_2=\frac{45.2 Torr\times 0.7273}{38.6 Torr}=0.8516

Mole fraction of alcohols in vapor phase y_1=0.1468\& y_2=0.8516

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