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2 years ago

What is NOT a reason that Cape Canaveral was chosen to be one of six locations for

Physics

1 answer:

prohojiy [21]2 years ago

4 0

It being near railroads is not a reason why Cape Canaveral was chosen to

be one of six locations for a NASA space center.

<h3>What is the Cape Canaveral?</h3>

The Cape Canaveral is a site which was chosen as a NASA space center for

the launching of rockets into space. It was chosen as a result of the factors

such as:

It being scarcely-populated.

It has a temperate climate.

It is situated by the ocean.

The temperate climate is located closer to the equator and has a high

centrifugal force which would aid launching of rockets. It was also chosen

because it was scarcely populated and situated by the ocean to prevent

lesser effect on land in the case of accidents and other factors.

Read more about Cape Canaveral here brainly.com/question/614447

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Which best describes how combustion works?

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The answer is A, it breaks down and releases thermal energy.

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3 years ago

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a 1210 kg roller coaster car is moving 6.33 m/s. as it approaches the station, brakes slow it down to 2.38 m/s over a distance o

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Answer:

4960 N

Explanation:

First, find the acceleration.

Given:

v₀ = 6.33 m/s

v = 2.38 m/s

Δx = 4.20 m

Find: a

v² = v₀² + 2aΔx

(2.38 m/s)² = (6.33 m/s)² + 2a (4.20 m)

a = -4.10 m/s²

Next, find the force.

F = ma

F = (1210 kg) (-4.10 m/s²)

F = -4960 N

The magnitude of the force is 4960 N.

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3 years ago

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What is the GPE of a 15,000 kg airplane sitting on the ground?

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3 years ago

An automobile traveling 95 km/h overtakes a 1.30-km-long train traveling in the same direction on a track parallel to the road.

SOVA2 [1]

Answer:

Same direction: t=234s; d=6.175Km

Opposite direction: t=27.53s; d=0.73Km

Explanation:

If the automobile and the train are traveling in the same direction, then the automobile speed relative to the train will be $v_{AT}=v_A-v_T$ (the train must see the car advancing at a lower speed), where $v_A$ is the speed of the automobile and $v_T$ the speed of the train.

So we have $v_{AT}=(95km/h)-(75Km/h)=20Km/h$ .

So the train (anyone in fact) will watch the automobile trying to cover the lenght of the train L at that relative speed. The time required to do this will be:

$t = \frac{L}{v_{AT}} = \frac{1.3Km}{20Km/h} = 0.065h=234s$

And in that time the car would have traveled (relative to the ground):

$d=v_At=(95Km/h)(0.065h)=6.175Km$

If they are traveling in opposite directions, we have to do all the same but using $v_{AT}=v_A+v_T$ (the train must see the car advancing at a faster speed), so repeating the process: