Answer:
The stoichiometric coefficient for aluminum is 2
Explanation:
Step 1: Data given
Aluminum metal = Al(s)
aqueous iron(III) oxide = Fe2O3(s)
aqueous aluminum oxide = Al2O3(s)
iron metal = Fe(s)
Step 2: The unbalanced equation
Al(s) + Fe2O3(s) → Al2O3(s) + Fe(s)
Step 3: Balancing the equation
On the left side we have 1x Al , on the right we have 2x Al (in Al2O3). To balance the amount of Al on both sides, we have to multiply Al (on the left side) by 2.
2Al(s) + Fe2O3(s) → Al2O3(s) + Fe(s)
On the left side we have 2x Fe (in Fe2O3) , on the right we have 1x Fe. To balance the amount of Fe on both sides, we have to multiply Fe (on the right side) by 2. Now the equation is balanced.
2Al(s) + Fe2O3(s) → Al2O3(s) +2Fe(s)
The stoichiometric coefficient for aluminum is 2
First, 55 g of Hg is 3.65 moles because one mole of Hg has a molar mass of 200.59
Then, the mole ratio of Hg to CaO is 8:4 or 2:1. SO we divide 3.65 by 2 to get 1.82 moles of CaO
This is the same as 102.06 grams because one mole of CaO has a molar mass of 56.0774
Hope this helps!
Answer:
Q = 360 Joules
Explanation:
specific heat of copper = 0.400 J/g° C
mass of copper = 30 g
initial temperature = 20.0°C
final temperature = 50.0°C
Using the formula:
Q = mcΔT
where;
Q = Heat Energy
Q = (30 × 0.400)(50-20)
Q = 360 Joules
Answer:
C₄F₈
Explanation:
Using their mole ratio to compute their mass
molar mass of carbon = 12.0107 g/mol
molar mass of fluorine gas = 37.99681
let x = mass of carbon
given mass of fluorine = 1.70 g
x / 12.01067 = 1.70 / 37.99687
cross multiply
x = ( 1.70 × 12) / 37.99687 = 20.4 / 37.99687 = 0.53688 g
mass of one mole of CF₂ = 0.53688 + 1.70 = 2.23688 g
number of mole of CF₂ = 8.93 g / 2.23688 = 3.992 approx 4
molecular formula of CF₂ = 4 (CF₂) = C₄F₈