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zaharov [31]
2 years ago
12

Using aluminium as an example, describe the key properties of p-block metals.

Chemistry
2 answers:
ruslelena [56]2 years ago
8 0

Answer:

Physical Properties of Aluminum

Aluminum has a lower density than any other commercial metal except magnesium. Given the right type of surface, aluminum makes an excellent reflector, especially for ultraviolet light.

Aluminum is an odorless, tasteless, silvery white metal. With increasing silicon and ductile and quite soft. The aluminum crystal has a face centered cubic structure.

The concentration of the lattice in the less pure metal results from the formation of impurity segregations. Purity also affects most other physical properties.

Aluminum has a lower density than any other commercial metals except magnesium.

Aluminum may also be used as a selective cold or hot wall or as a body approximating to the effect of a black body. In the infrared region the reflectivity of aluminum is exceeded only slightly by that of gold and silver.

Chemical Properties of Aluminum

1. Reaction of Aluminum with Air

Generally, Aluminum metal does not react with air as its surface is covered with a thin layer of oxide that helps protect the metal from attack by air. However, in case the oxide layer gets damaged, and the Aluminum metal gets exposed, it reacts again with oxygen forming amphoteric oxide (Aluminum (lll) Oxide), Al2O3.

4Al (s) + 3O2 (l) → 2Al2O3 (s)

Explanation:

Properties of P-Block Metals These metals have classical metal characteristics that they are shiny, good conductors of heat and electricity and also, they lose electrons. They have high melting points and react with non-metals to form ionic compounds.

olga nikolaevna [1]2 years ago
6 0

Answer:

P-block metals have classic metal characteristics like they are shiny, they are good conductors of heat and electricity, and they lose electrons easily. These metals have high melting points and readily react with nonmetals to form ionic compounds.

Explanation:

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You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8
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Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is pK_a  =7.82

Explanation:

From the question we are told

    The volume of base is  V_B = 26.mL = 0.0260L

     The pH of solution is  pH =  7.82

      The concentration of the acid is C_A = 0.1M

From the pH we can see that the titration is between a strong base and a weak acid

 Let assume that the the volume of acid is  V_A = 18mL= 0.018L

Generally the concentration of base

                    C_B = \frac{C_AV_A}{C_B}

Substituting value  

                     C_B = \frac{0.1 * 0.01800}{0.0260}

                    C_B= 0.0692M

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

           HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}

Now before the reaction the number of mole of base is  

            No \ of \ moles[N_B]  =  C_B * V_B

Substituting value  

                    N_B = 0.01300 * 0.0692

                         = 0.0009 \ moles    

                                 

Now before the reaction the number of mole of acid is  

            No \ of \ moles  =  C_B * V_B

Substituting value  

                    N_A = 0.01800 *0.1

                         = 0.001800 \ moles

Now after the reaction the number of moles of  base is  zero  i.e has been used up

    this mathematically represented as

                         N_B ' = N_B - N_B = 0

    The  number of moles of acid is  

             N_A ' = N_A  - N_B

                   = 0.0009\ moles

The pH of this reaction can be mathematically represented as

                 pH  = pK_a + log \frac{[base]}{[acid]}

Substituting values

                  7.82 = pK_a +log \frac{0.0009}{0.0009}

                  pK_a  =7.82        

                     

             

                                 

       

           

                     

8 0
3 years ago
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