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Mekhanik [1.2K]
2 years ago
9

Calculate the volume in dm3 occupied by 26.4 g of carbon dioxide​

Chemistry
1 answer:
Mama L [17]2 years ago
7 0
  • Density of carbon dioxide=1564kg/m^3
  • Mass=26.4g=0.0264kg

\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \sf\longmapsto Volume=\dfrac{Mass}{Density}

\\ \sf\longmapsto Volume=\dfrac{0.0264}{1564}

\\ \sf\longmapsto Volume=1.687m^3=1.69m^3

  • 1m^3=1000dm^3

\\ \sf\longmapsto Volume=1.69(1000)=1690dm^3

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No matter how much water a human drinks, the kidneys are always regulating various aspects of the blood, including _____________
Snowcat [4.5K]

The answers are I, II and IV

No matter how much water a human drinks, the kidneys are always regulating various aspects of the blood, including the pH of the blood, the plasma concentration of iron ions and the plasma concentration of potassium ions.

 






3 0
3 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
3 years ago
What of the following is NOT a common property of metals?
Yuri [45]

Answer:

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Explanation:i need points

5 0
2 years ago
Consider the following intermediate reactions.
Alja [10]

2.1648 kg of CH4 will generate 119341 KJ of energy.

Explanation:

Write down the values given in the question

CH4(g) +2 O2 → CO2(g) +2 H20 (g)

ΔH1 = - 802 kJ

2 H2O(g)→2 H2O(I)

ΔH2= -88 kJ

The overall chemical reaction is

CH4 (g)+2 O2(g)→CO2(g)+2 H2O (I) ΔH2= -890 kJ

CH4 +2 O2 → CO2 +2 H20

(1mol)+(2mol)→(1mol+2mol)

Methane (CH4) = 16 gm/mol

oxygen (O2) =32 gm/mol

Here 1 mol CH4 ang 2mol of O2 gives 1mol of CO2 and 2 mol of 2 H2O

which generate 882 KJ /mol

Therefore to produce 119341 KJ of energy

119341/882 = 135.3 mol

to produce 119341 KJ of energy, 135.3 mol of CH4 and 270.6 mol of O2 will require

=135.3 *16

=2164.8 gm

=2.1648 kg of CH4

2.1648 kg of CH4 will generate 119341 KJ of energy

4 0
3 years ago
Read 2 more answers
In prolonged fasting conditions acetyl-coa generated from the breakdown of amino acids and fatty acids does not enter the citric
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<h3>What is amino acids?</h3>

Amino acids are chemical molecules having side chains (R groups) unique to each amino acid as well as amino and carboxylic acid (CO2H) functional groups.

Every amino acid contains the elements carbon (C), hydrogen (H), oxygen (O), and nitrogen (N) (CHON); in addition, the side chains of cysteine and methionine contain sulfur (S), while the less frequent amino acid selenocysteine has selenium (Se). As of 2020, it is known that more than 500 naturally occurring amino acids make up the monomer units of peptides, including proteins.

Despite the fact that there are only 22 proteins, 20 of them have unique specified codons, and another two have unique coding mechanisms: All eukaryotes contain selenocysteine, and pyrrolysine is also present.

To learn more about amino acids from the given link:

brainly.com/question/21327676

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7 0
2 years ago
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