Answer:
Molarity = 3 M
Explanation:
Given data:
Volume of solution = 2 L
Number of moles of HCl = 6 mol
Molarity = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
by putting values,
Molarity = 6 mol / 2 L
Molarity = 3 M (M = mol/L)
Answer: gasoline
Explanation: Gasoline is a mixture of many different hydrocarbons: alkanes (paraffins), cycloalkanes and alkenes (olefins). Salt and carbon dioxide are chemical compounds, aluminium (Al) is an chemical element.
Answer:
Explanation:
Cadmium:(Cd)
Cadmium is transition metal present in group twelve. It is soft metal and properties are similar to the other group members like zinc and mercury. Its atomic number is forty eight and have two valance electrons.
Electronic configuration:
Cd₄₈ = [Kr] 4d¹⁰ 5s²
Vanadium: (V)
It is present in group five. It is malleable and ductile transition metal. Its atomic number is twenty three. Vanadium have five valance electrons.
Electronic configuration:
V₂₃ =[Ar] 3d³ 4s²
Xenon: Xe
Xenon is present in group eighteen. It is noble gas. Its outer most valance shell is complete that's why it is inert. its atomic number is fifty four. Xenon have eight valance electrons.
Electronic configuration:
Xe₅₄ = [Kr] 4d¹⁰ 5s² 5p⁶
Iodine: (I)
Iodine is present in group seventeen. Its outer most valance shell have seven electrons. Iodine is the member of halogen family. It gain one electron to complete the octet. its atomic number is fifty three.
Electronic configuration:
I₅₃ = [Kr] 4d¹⁰ 5s² 5p⁵
Potassium: (K)
Potassium is present in group one. it is alkali metal. Its atomic number is nineteen. Its valance shell has one electron. Potassium loses its one valance electron and gets stable electronic configuration.
Electronic configuration:
K₁₉ = [Ar] 4s¹
Strontium: Sr
Strontium is present in group two. it is alkaline earth metal. its atomic number is thirty eight and have two valance electrons.
Electronic configuration:
Sr₃₈ = [Kr] 5s²
