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Nadusha1986 [10]
2 years ago
15

What are some paradigms from history that have been proven inaccurate or incomplete

Engineering
1 answer:
frozen [14]2 years ago
4 0
That the world is flat. Brainliest?
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1. Implement the k-means clustering algorithm either in Java or Python. • The program should be executable with at least 3 param
givi [52]

Answer:

The code for this Question in Python is as follows:

matplotlib inline

from copy import deepcopy

import numpy as np

import pandas as pd

from matplotlib import pyplot as plt

plt.rcParams['figure.figsize'] = (16, 9)

plt.style.use('ggplot')

# Importing the dataset

data = pd.read_csv('xclara.csv')

print(data.shape)

data.head()

# Getting the values and plotting it

f1 = data['V1'].values

f2 = data['V2'].values

X = np.array(list(zip(f1, f2)))

plt.scatter(f1, f2, c='black', s=7)

# Number of clusters

k = 3

# X coordinates of random centroids

C_x = np.random.randint(0, np.max(X)-20, size=k)

# Y coordinates of random centroids

C_y = np.random.randint(0, np.max(X)-20, size=k)

C = np.array(list(zip(C_x, C_y)), dtype=np.float32)

print(C)

# To store the value of centroids when it updates

C_old = np.zeros(C.shape)

# Cluster Lables(0, 1, 2)

clusters = np.zeros(len(X))

# Error func. - Distance between new centroids and old centroids

error = dist(C, C_old, None)

# Loop will run till the error becomes zero

while error != 0:

   # Assigning each value to its closest cluster

   for i in range(len(X)):

       distances = dist(X[i], C)

       cluster = np.argmin(distances)

       clusters[i] = cluster

   # Storing the old centroid values

   C_old = deepcopy(C)

   # Finding the new centroids by taking the average value

   for i in range(k):

       points = [X[j] for j in range(len(X)) if clusters[j] == i]

       C[i] = np.mean(points, axis=0)

   error = dist(C, C_old, None)

# Initializing KMeans

kmeans = KMeans(n_clusters=4)

# Fitting with inputs

kmeans = kmeans.fit(X)

# Predicting the clusters

labels = kmeans.predict(X)

# Getting the cluster centers

C = kmeans.cluster_centers_

fig = plt.figure()

ax = Axes3D(fig)

ax.scatter(X[:, 0], X[:, 1], X[:, 2], c=y)

ax.scatter(C[:, 0], C[:, 1], C[:, 2], marker='*', c='#050505', s=1000)

4 0
4 years ago
How to write a 5bit register if a series is moved to the shift register from left to right
mr_godi [17]

The Bidirectional Shift Register is the shift register that allows one to write a 5bit register if the series is shifted from left to right.

<h3>What is a value of a 5-bit register?</h3>

A 5-bit register is valuable because it can represent up to 32 items. It is to be noted that a bit is a digit that is binary that is indicative of two states.

While a 5-bit register can have a possible number of 32 values,

  • 6 can hold 64;
  • 7 can hold 128;
  • 8 can hold 256 etc.

Learn more about registers at;
brainly.com/question/19091159
#SPJ1

8 0
2 years ago
PLEASE HELP, I WILL MARK AS BRAINLIEST, URGENT!!!
Feliz [49]
<h2>Answer:-</h2>

1.Enzymes used by fireflies are used to improve <u>Food Safety </u><u>.</u>

2.They have seven different kinds of silk.

Option A

<h2>Mark it BRAINLIST </h2>

3 0
3 years ago
Scissors is to cut as?​
lidiya [134]

Answer:

yes...? uhm I don't know what this means

6 0
3 years ago
In a constant-head permeability test in the laboratory, the length of the soil specimen is 275 mm and its cross sectional area i
sattari [20]

Answer:

The head difference across the soil specimen is 39.29 cm and the discharge velocity is 0.02 cm/s

Explanation:

The head difference across the soil specimen is:

k=\frac{QL}{Aht}

Where

k = hydraulic conductivity = 0.014 cm/s

Q = volume of water collected = 150 cm³/min = 2.5cm³/s

L = length of the soil specimen = 275 mm = 27.5 cm

A = area = 125 cm²

Replacing:

0.014=\frac{2.5*27.5}{125*h*1} \\h=39.29cm

The hydraulic gradient is:

i=\frac{h}{L} =\frac{39.29}{27.5} =1.43

The discharge velocity is:

v = k*i = 0.014 * 1.43 = 0.02 cm/s

8 0
3 years ago
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