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Rom4ik [11]
2 years ago
13

A construction crew is paving a road. The crew has already paved 1,000 square feet and can pave at a rate of 300 square feet of

road per hour. The function f(x) = 300x 1,000 represents this situation. What is f(3), and what does it represent?.
Physics
1 answer:
anyanavicka [17]2 years ago
6 0

f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount.

Mathematical models are representations of real situations. Models often serve the purpose of prediction and can help to explain and simplify certain mathematical problems.

The model; f(x) = 300x + 1,000 represents the number of additional square feet that can be paved in an hour after 1,000 square feet has already been paved.

From the above we can see that the correct answer is; "900 square feet; f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount."

Learn more: brainly.com/question/731147

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Difference between moment and displacement​
harkovskaia [24]

<u>Displacement</u> is the difference between final position and initial position.

<u>Momentum</u> is the quantity of motion contained by an object.

  • It is the product of <em><u>mass and velocity.</u></em>
7 0
2 years ago
Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the accelerat
vichka [17]
The period of a pendulum is given by
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the pendulum length and g is the gravitational acceleration.

We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
\frac{T_m}{T_e} =  \frac{2 \pi  \sqrt{ \frac{L}{g_m} } }{2 \pi  \sqrt{ \frac{L}{g_e} } }=    \sqrt{ \frac{g_e}{g_m} }
where the labels m and e refer to "Moon" and "Earth".

Since the gravitational acceleration on Earth is g_e = 9.81 m/s^2 while on the Moon is g_m=1.63 m/s^2, the ratio between the period on the Moon and on Earth is
\frac{T_m}{T_e}= \sqrt{ \frac{g_e}{g_m} }= \sqrt{ \frac{9.81 m/s^2}{1.63 m/s^2} }=2.45

3 0
3 years ago
A force of 30.0 N is applied to a 3.00 kg object for 3.00 seconds. Calculate the velocity experienced by the object.
olganol [36]

Answer:

Explanation:

F = ma and

a=\frac{v}{t}

We have F, we have m, but in order to solve for v, we need a.

30.0 = 3.00a so

a = 10.0 m/s/s. Plug that in for a in the second equation and solve for v:

10.0=\frac{v}{3.00} so

v = 10.0(3.00) so

v = 30.0 m/s

6 0
2 years ago
If the man on the left pulls on the object with a force of 500 N and the man on the right pulls on the object with a force of 75
Igoryamba
Force is a vector quantity
so pulling from opposite side will be negative
so
750+(-500)= 250N
C is the right answer
becauseause the man on the right applies greater force.
3 0
3 years ago
Speed=100m/sec<br> Frequency=10 Hz<br> Wavelength=?
elena-14-01-66 [18.8K]

Answer:

Wavelength = 10 m

Explanation:

Given:

Speed = 100 ms^{-1}

Frequency = 10 Hz = 10 s^{-1}

To find : Wavelength = ?

We know that the relationship between wavelength λ, frequency f and speed v is given by the equation

    v = fλ

Therefore wavelength λ = v/f

                                        = 100 ms^{-1} / 10 ms^{-1}

                                        = 10 m

Hence wavelength = 10 m

4 0
3 years ago
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