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Allushta [10]
2 years ago
10

Explain why sugar was used in this experiment. How does the experiment relate to a baker adding yeast to bread to make it rise?

Physics
1 answer:
tia_tia [17]2 years ago
7 0

Answer:

Yeast can use oxygen to release the energy from sugar (like you can) in the process called "respiration". ... So, the more sugar there is, the more active the yeast will be and the faster its growth (up to a certain point - even yeast cannot grow in very strong sugar - such as honey).

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What is fluorine sidekicks
Talja [164]

Fluorine is the most reactive and the most electronegative of all the elements. Fluorine is a pale yellow, diatomic, highly corrosive, flammable gas, with a pungent odor. It is the lightest halogen.

6 0
3 years ago
Yuck! This statement represents which of the folllwoing functions of language
rodikova [14]

Their is NO following options for us to choose from. Please resend in order for somebody's help!  

thanks!

7 0
3 years ago
Consider a long cylindrical charge distribution of radius R with a uniform charge density rho. Find the electric field at distan
ahrayia [7]

Answer: Ok, first lest see out problem.

It says it's a Long cylindrical charge distribution, So you can ignore the border effects on the ends of the cylinder.

Also by the gauss law we know that E¨*2*pi*r*L = Q/ε0

where Q is the total charge inside our gaussian surface, that will be a cylinder of radius r and heaight L.

So Q= rho*volume= pi*r*r*L*rho

so replacing : E = (1/2)*r*rho/ε0

you may ask, ¿why dont use R on the solution?

since you are calculating the field inside the cylinder, and the charge density is uniform inside of it, you don't see the charge that is outside, and in your calculation actuali doesn't matter how much charge is outside your gaussian surface, so R does not have an effect on the calculation.

R would matter if in the problem they give you the total charge of the cylinder, so when you only have the charge of a smaller r radius cylinder, you will have a relation between r and R that describes how much charge density you are enclosing.

3 0
3 years ago
You are conducting an experiment inside an elevator that can move in a vertical shaft. A load is hung vertically from the ceilin
Ivan

Answer: The elevator must be accelerating.

Explanation:

As the tension force is opposing to the the force of gravity on the load which is hung vertically, and the tension force can adopt any value in order to comply with Newton's 2nd law, if the tension force is less than the force due to gravity, this means that all system is not in equilibrium, so it must be accelerating.

If we assume that the downward is the positive direction, we can write:

mg - T = ma

If T = 0.9 mg, ⇒ mg (1-0.9) =0.1 mg = m a ⇒a = 0.1 g , in downward direction.

5 0
2 years ago
For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency
Angelina_Jolie [31]

Answer:

2.7 J

Explanation:

The energy of one photon is given by

E=hf

where

h is the Planck constant

f is the frequency

For the photons in this problem,

f=6.8\cdot 10^9 Hz

So the energy of one photon is

E_1=(6.63\cdot 10^{-34})(6.8\cdot 10^9 )=4.5\cdot 10^{-24} J

The number of photons contained in 1.0 mol is

N_A = 6.022\cdot 10^{23} mol^{-1} (Avogadro number)

So the total energy of N_A photons contained in 1.0 mol is

E=N_A E_1 =(6.022\cdot 10^{23})(4.5\cdot 10^{-24})=2.7 J

3 0
3 years ago
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