Question

g What is the molality of a solution produced using 15.2 g of Calcium chloride and 345 g of methanol (CH3OH)

Answer 1

Considering the definition of molality, the molality of a solution produced using 15.2 g of calcium chloride and 345 g of methanol is 0.397 $\frac{moles}{Kg}$.

Molality

Molality is a measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent.

This is, molality is the ratio of the number of moles of any dissolved solute to kilograms of solvent:

The Molality of a solution is determined by the expression:

$Molality= \frac{number of moles of solute}{kilograms of solvent}$

Molality is expressed in units $\frac{moles}{Kg}$.

Solute and solvent

The solution is a homogeneous mixture of two or more components that have the same chemical and physical properties in a single phase. A solution is made up of two main components: the solute and the solvent.

That is, the solute and the solvent are the components of a chemical solution, that is, of a homogeneous mixture that occurs when one or more substances are dissolved in another substance.

The solute is the substance that dissolves in a solution. In solution, the solute is usually found in a lower proportion than the solvent.

Solvent, also known as solvent, is the substance in which a solute dissolves, resulting in a chemical solution. Generally, the solvent is the component that is found in the highest proportion in the solution. It will always be the solvent who will determine the state of the matter that will have the solution.

This case

In this case, since calcium chloride is found in a smaller proportion and methanol in a greater proportion, calcium chloride is the solute and methanol is the solvent.

Being the molar mass of calcium chloride 110.98 g/mol,  the number of moles of the compound contained in 15.2 g is calculated by:

$15.2 gramsx\frac{1 mole}{110.98grams}$= 0.137 moles of calcium chloride

On the other side, you have 345 g of methanol. This is, you have 0.345 kg of methanol (being 1000 g= 1 kg).

Then, considering the solute and solvent, the molality can be calculated as:

$Molality= \frac{0.137 moles}{0.345 kg}$

Solving:

Molality= 0.397 $\frac{moles}{Kg}$

Finally, the molality of a solution produced using 15.2 g of calcium chloride and 345 g of methanol is 0.397 $\frac{moles}{Kg}$.

Learn more about:

• solute and solvent:

1. brainly.com/question/2614077?referrer=searchResults

• molality

1. brainly.com/question/20366625?referrer=searchResults
2. brainly.com/question/4580605?referrer=searchResults