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2 years ago

An electric clothes dryer draws 15 A at 220 V. If the clothes put into the dryer have a mass of 7.0 kg

Physics

1 answer:

xz_007 [3.2K]2 years ago

6 0

Answer:

Explanation:

7.0 - 4.0 = 3.0 kg water

3.0 kg(2.26 x 10⁶ J/kg = 6.78 x 10⁶ J

220 V(15 A) = 3300 W

1 W = 1 J/s

6.78 x 10⁶ J / 3300 J/s = 2054 s

2054 s / 60 s/min = 34 min

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The wavelength of red helium-neon laser light in air is 632.8 nm.

e-lub [12.9K]

(a) $4.74\cdot 10^14 Hz$

The frequency of an electromagnetic wave is given by:

$f=\frac{c}{\lambda}$

where

$c=3.0\cdot 10^8 m/s$ is the speed of the wave in a vacuum (speed of light)

$\lambda$ is the wavelength

In this problem, we have laser light with wavelength

$\lambda=632.8 nm=6.33\cdot 10^{-7} m$ . Substituting into the formula, we find its frequency:

$f=\frac{3.0\cdot 10^8 m/s}{6.33\cdot 10^{-7} m}=4.74\cdot 10^14 Hz$

(b) 427.6 nm

The wavelength of an electromagnetic wave in a medium is given by:

$\lambda=\frac{\lambda_0}{n}$

where

$\lambda_0$ is the original wavelength in a vacuum (approximately equal to that in air)

$n$ is the index of refraction of the medium

In this problem, we have

$\lambda_0=632.8 nm$

n = 1.48 (index of refraction of glass)

Substituting into the formula,

$\lambda=\frac{632.8 nm}{1.48}=427.6 nm$

(c) $2.03\cdot 10^8 m/s$

The speed of an electromagnetic wave in a medium is

$v=\frac{c}{n}$

where c is the speed of light in a vacuum and n is the refractive index of the medium.

Since in this problem n=1.48, we find

$v=\frac{3\cdot 10^8 m/s}{1.48}=2.03\cdot 10^8 m/s$

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4 years ago

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Explanation:

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3 years ago

The density of an object is how much matter it contains. <br><br> a. True <br><br> b. False

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Answer:

False

Explanation:

The density is mass divided by volume

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4 years ago