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Iteru [2.4K]
2 years ago
8

Why do we always use water as a reference material when determining the relative density of a substance

Physics
2 answers:
enyata [817]2 years ago
8 0

Answer:

Specific gravity for liquids is nearly always measured with respect to water at its densest

Explanation:

Archy [21]2 years ago
8 0

Answer:

Because of it being able to become a gas, a liquid, and solid, and because its used in lots of chemical experiments. (also because its easier to describe it than any other liquid)

Explanation:

1. Water is used in most Chemicals, therefore its being used as a reference material.

2. W

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A tiger covers a distance of 600 m in 15 minutes what is a speed of a tiger?​
aliya0001 [1]

Answer: 2.4 km/hr

Explanation:

Distance = 600m

Time= 15 minutes = 15 x 60 second/minute = 900 seconds

Speed =  \frac{Distance}{Time}  =  \frac{600}{900}  = \frac{2}{3} m/sec

⇒ \frac{2}{3} x \frac{18}{5} = 2.4 km/hr (1 m/sec = 3.6 km/hr)

5 0
3 years ago
HELPPP!!! During a soccer game, a player kicks the winning goal. When is work being done by the player?
zimovet [89]

Answer:

when the player’s foot is in contact with the ball

Explanation:

7 0
3 years ago
Which of these formulas represents 1 atom of sodium (Na) chemically combined with another element?
Andru [333]
The answer is B. because NaCl are just two elements with one atom from each element
3 0
3 years ago
Read 2 more answers
An aluminum bar 600mm long, with diameter 40mm long has a hole drilled in the center of the bar.The hole is 30mm in diameter and
Svetradugi [14.3K]

Answer:

Total contraction on the Bar  = 1.22786 mm

Explanation:

Given that:

Total Length for aluminum bar = 600 mm  

Diameter for aluminum bar  = 40 mm

Hole diameter  = 30 mm

Hole length = 100 mm

elasticity for the aluminum is 85GN/m² = 85 × 10³ N/mm²

compressive load P = 180 KN = 180  × 10³ N

Calculate the total contraction on the bar = ???

The relation used in  calculating the contraction on the bar is:

\delta L = \dfrac{P *L }{A*E}

The relation used in  calculating the total contraction on the bar can be expressed as :

Total contraction in the Bar = (contraction in part of bar without hole + contraction in part of bar with hole)

i.e

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Let's find the area of cross section without the hole and with the hole

Area of cross section without the hole is :

Using A = πd²/4

A = π (40)²/4

A = 1256.64 mm²

Area of cross section with the hole is :

A = π (40²-30²)/4

A = 549.78 mm²

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Total contraction on the Bar  = \dfrac{180 *10^3 \N  }{85*10^3 \ N/mm^2} [\dfrac{500}{1256.64}+ \dfrac{100}{549.78}]

Total contraction on the Bar  = 2.117( 0.398 + 0.182)

Total contraction on the Bar  = 2.117*(0.58)

Total contraction on the Bar  = 1.22786 mm

5 0
4 years ago
According to the law of conservation of energy,
vova2212 [387]

Explanation:

energy cannot be created or destroyed, but only changed from one form to another or transferred from one object to another.

5 0
4 years ago
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