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iogann1982 [59]
2 years ago
12

ONE sound wave travels through two containers of different gasses. Wave through container 1 has a wavelength of 1.2 m. Wave thro

ugh container 2 has a wavelength of 3.6 m. The frequency of wave through container 2 must be __________ the frequency of wave through container 1.
a. one-ninth


b. one-third


c. the same as


d. three times larger than
Physics
1 answer:
Zarrin [17]2 years ago
7 0
I’m not 100% but the answer is b
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A proton has been accelerated from rest through a potential difference of -1000 v . part a what is the proton's kinetic energy,
wlad13 [49]
We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:
\Delta U + \Delta K=0
which means
\Delta K = - \Delta U
The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference (\Delta V=-1000 V):
\Delta U = q \Delta V=(1 eV)(-1000 V)=-1000 eV
Therefore, the kinetic energy gained by the proton is
\Delta K = -(-1000 eV)=1000 eV
<span>And since the initial kinetic energy of the proton was zero (it started from rest), then this 1000 eV corresponds to the final kinetic energy of the proton.</span>
4 0
3 years ago
Read 2 more answers
A ball is kicked horizontally from a 60 meter tall cliff at 10 m/s. How far from
o-na [289]

Hi there!

We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.

\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}

There is NO initial vertical velocity, so:

\large\boxed{\Delta d= \frac{1}{2}at^2}}

Rearrange to solve for time:

2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}

Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)

t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s

Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:

\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}

6 0
2 years ago
I will give Brainliest to whoever can answer!!!!
Alexus [3.1K]

Answer:

The nodes and anti nodes would reverse roles.

Explanation:

I believe it has to do with the path differences. If waves are in phase, then the path differences are such that the waves reach the screen with crests superimposing crests and troughs superimposing troughs. This happens when the periods of each wave are equal or the paths themselves differ by a whole number multiple of the wavelength (λ, 2λ, 3λ, ...).

Now make these waves out of phase. Then half of the waves will travel half a wavelength farther than the rest. So the path difference will be 0.5λ, 1.5λ, 2.5λ, ....

4 0
3 years ago
An archer pulls her bowstring back 0.396 m by exerting a force that increases uniformly from zero to 237 N. (a) What is the equi
tatyana61 [14]

Answer:

(a) The equivalent spring constant is 598.485 N/m

(b) The work done is 46.926 J

Explanation:

From Hooke's law of elasticity

K (spring constant) = F/e

F is the range of force exerted = 237 - 0 = 237 N

e is the extension of bowstring = 0.396 m

K = F/e = 237/0.396 = 598.485 N/m

Work done = 1/2 Fe = 1/2 × 237 × 0.396 = 46.926 J

6 0
3 years ago
Frank has a sample of steel that weighs 80 grams. If the density of his sample of steel is 8 g/cm3, what is the sample’s volume?
Naddik [55]
10 cm3 because the density equition is d = m/v
7 0
3 years ago
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