Answer:
C₆H₁₂O₆ + 6O₂ —> 6CO₂ + 6H₂O
Explanation:
Glucose (C₆H₁₂O₆) react with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O).
The equation can be written as follow:
C₆H₁₂O₆ + O₂ —> CO₂ + H₂O
The above equation can be balance as illustrated below:
C₆H₁₂O₆ + O₂ —> CO₂ + H₂O
There are 6 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 6 in front of CO₂ as shown below:
C₆H₁₂O₆ + O₂ —> 6CO₂ + H₂O
There are 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H₂O as shown below:
C₆H₁₂O₆ + O₂ —> 6CO₂ + 6H₂O
There are a total of 8 atoms of O on the left side and a total of 18 atoms on the right side. It can be balance by 6 in front of O₂ as shown below:
C₆H₁₂O₆ + 6O₂ —> 6CO₂ + 6H₂O
Now, the equation is balanced.
Answer:
The answer to your question is the mass of solute = 53.5 g
Explanation:
Data
mass of solution = 482 g
mass of solute = ?
mass percent = 11.1 %
Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution
Process
1.- Write the formula
Mass percent = mass of solute / mass of solution x 100
-Solve for mass of solute
mass of solute = Mass percent x mass of solution / 100
2.- Substitution
mass of solute = 11.1 x 482 / 100
3.- Simplification
mass of solute = 5350.2 / 100
4.- Result
mass of solute = 53.5g
3618 is the numbers for the graph