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2 years ago

Advantages and disadvantages of titration?

Chemistry

1 answer:

alisha [4.7K]2 years ago

5 0

Answer:

What are the advantages of titration?

Titrimetric analysis commonly referred to as volumetric analysis offers distinct advantages over cumbersome gravimetric methods:

Speed of analysis.

Instantaneous completion of reactions.

Greater accuracy due to minimization of material loss involved in decanting, filtration, precipitation or similar operations.

Explanation:

Disadvantages

It is a destructive method often using up relatively large quantities of the substance being analysed.

It requires reactions to occur in a liquid phase, often the chemistry of interest will make this inappropriate.

It can produce significant amounts of chemical waste which has to be disposed of.

It has limited accuracy.

hope this helps Please inform me if its helpful

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aleksklad [387]

Answer:

<h3>The answer is 41.05 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual density = 0.95 g/mL

error = 0.95 - 0.56 = 0.39

So we have

$p(\%) = \frac{0.39}{0.95} \times 100 \\ = 41.0526315...$

We have the final answer as

Hope this helps you

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3 years ago

Determine the rate of a reaction that follows the rate law:

3241004551 [841]

Answer:

Explanation:

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8 0

2 years ago

Read 2 more answers

Answer these please! 23 points!

Aleksandr-060686 [28]

For the first question the answer is

The "s" orbital can only hold a maximum of two electrons. ... Elements in the each group have the same number of valence electrons. Why is hydrogen set apart by itself? Hydrogen does not belong to a single group b/c it can be considered an alkali metal, but it is also a gas.

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2 years ago

You are running a rather large scale reaction where you prepare the grignard reagent phenylmagnesium bromide by reacting 210.14

almond37 [142]

Answer:

We would expect to form 7.35 moles of grignard reagent.

Explanation:

Step 1: Data given

Mass of magnesium = 210.14 grams

Volume bromobenzene = 772 mL

Density of bromobenzene = 1.495 g/mL

Molar mass of Mg = 24.3 g/mol

Molar mass of bromobenzene = 157.01 g/mol

Step 2: The balanced equation

C6H5Br + Mg ⇒ C6H5MgBr

Step 3: Calculate mass of bromobenzene

Mass bromobenzene = density bromobenzene * volume

Mass bromobenzene = 1.495 g/mL * 772 mL

Mass bromobenzene = 1154.14 grams

Step 4: Calculate number of moles bromobenzene

Moles bromobenzene = mass bromobenzene / molar mass bromobenzene

Moles bromobenzene = 1154.14g / 157.01 g/mol

Moles bromobenzene = 7.35 moles

Step 5: Calculate moles of Mg

Moles Mg = 210.14 grams /24.3 g/mol

Moles Mg = 8.65 moles

Step 6: The limiting reactant

The mole ratio is 1:1 So the bromobenzene has the smallest amount of moles, so it's the limiting reactant. It will be completely consumed ( 7.35 moles). Magnesium is in excess, There will react 7.35 moles. There will remain 8.65 - 7.35 = 1.30 moles

Step 7: Calculate moles of phenylmagnesium bromide

For 1 mole of bromobenzene, we need 1 mole of Mg to produce 1 mole of phenylmagnesium bromide

For 7.35 moles bromobenzene, we have 7.35 moles phenylmagnesium bromide

We would expect to form 7.35 moles of grignard reagent.

5 0

2 years ago

How many grams of glucose are in 11.5 moles?

mestny [16]

There are 2071.79 grams of glucose in 11.5 moles.

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2 years ago