A sample of gas is measured to be 375 ml at 1.15 atm. The pressure

Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions. If 0.212 g of KHP are dissolve

maxonik [38]

The molarity of the NaOH solution is 0.03 M

We'll begin by calculating the mole of the KHP

Mass = 0.212 g
Molar mass = 204.22 g/mol
Mole of KHP =?

Mole = mass /molar mass

Mole of KHP = 0.212 / 204.22

Mole of KHP = 0.001 mole

Next, we shall determine the molarity of the KHP solution

Mole of KHP = 0.001 mole
Volume = 50 mL = 50/1000 = 0.05 L
Molarity of KHP =?

Molarity = mole / Volume

Molarity of KHP = 0.001 / 0.05

Molarity of KHP = 0.02 M

Finally , we shall determine the molarity of the NaOH solution

KHP + NaOH —> NaPK + H₂O

From the balanced equation above,

The mole ratio of the acid, KHP (nA) = 1
The mole ratio of base, NaOH (nB) = 1

From the question given above, the following data were obtained:

Volume of acid, KHP (Va) = 50 mL
Molarity of acid, KHP (Ma) = 0.02 M.
Volume of base, NaOH (Vb) = 35 mL
Molarity of base, NaOH (Mb) =?

MaVa / MbVb = nA / nB

(0.02 × 50) / (Mb × 35) = 1

1 / (Mb × 35) = 1

Cross multiply

Mb × 35 = 1

Divide both side by 35

Mb = 1 / 35

Mb = 0.03 M

Thus, the molarity of the NaOH solution is 0.03 M

Complete question:

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6 0

3 years ago

Use the half-reaction method to balance the following equation in acidic solution. It is not necessary to include any phases of

yawa3891 [41]

Answer:

2H⁺ + 2MnO4⁻ + 3CN⁻ → 2MnO₂ + H₂O + 3CNO⁻

Explanation:

CN⁻ + MnO4⁻ → CNO⁻ + MnO₂

In right side permangante, with Mn element has +7 as oxidation number.

In the MnO₂, Mn acts with +4.

This is the half reaction of reduction, where the Mn has gained 3 electrons.

in right side, cianide with C element has +2 as oxidation number. In the anion cianate, C acts with +4.

The oxidation number has increased in this half reaction. It's oxidation where the C, has lost 2 elecontrons

( 4H⁺ + MnO4⁻ + 3e⁻ → MnO₂ + 2H₂O ) .2

(H₂O + CN⁻ → CNO⁻ + 2e⁻ + 2H⁺) .3

I have to add water, to ballance the amount of oxygens and protons to ballance H, in the opposite side

To ballance the half reactions, I have to multiply x2 (reduction) and x3 (oxidation) so I can cancel, the electrons.

2H⁺ + 2MnO4⁻ + 3CN⁻ → 2MnO₂ + H₂O + 3CNO⁻

The electrons are now cancelled, and I can also modify water. In reactant side I have 3H₂O and in product side, I have 4H₂O so, H₂O in right side is gone so I finally obtained 1 H₂O on left. I had 8H⁺ on right, and 6H⁺ on left, so finally I obtained 2H⁺ on right, and the protons of product side are gone.

6 0

3 years ago

What happens in nuclear fission reactions?

Dmitry [639]

Answer:

in nuclear fission, an unstable atom splits into 2 or more smaller pieces that are more stable and releases energy in the process. the fission process also releases extra neutrons which can split additional atoms, resulting in a chain reaction that releases a lot of energy

8 0

3 years ago

Read 2 more answers

A solution has a pOH of 8.7 so what is the pH of the solution? Is the solution acidic, basic, or neutral?

RSB [31]

PH + pOH = 14

pH = 14 - pOH

pH = 14 - 8.7

pH = 5,3

This solution is <u>acidic</u>.

If pH<7 - acidic
If pH=7 - neutral
If pH>7 - basic

5 0

3 years ago

Read 2 more answers

Describe how lead sulfate can be prepared using silver hydroxide

Anastaziya [24]

Answer: