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inysia [295]
2 years ago
12

What element is classified as an alkali metal?

Chemistry
2 answers:
Deffense [45]2 years ago
5 0

Answer:

hydrogen, lithium, sodium, potassium, rubidium, cesium, and francium

Explanation:

Any element in the first colon (group 1) of the periodic table is classified as alkali metal

castortr0y [4]2 years ago
3 0

Answer: Lithium is correct.

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2 What is the correct sequence of steps for the preparation of a pure sample of copper(II) sulfate
Lina20 [59]

Answer:

The correct answer is - B. dissolving → evaporation filtration → crystallisation

Explanation:

The method of the preparation of a pure sample of copper(II) sulfate from dilute sulfuric acid and copper II oxide is given as follows:

step 1. Adding dilute sulfuric acid into a beaker. Using bunsen burner heat the beaker.

step 2. Adding the copper (II) oxide into the beaker and give it a little time at a time to the warm dilute sulfuric acid and stir

step 3. Filtering the mixture into an evaporating vessel to remove the excess copper (II) oxide and water from the filtrate.

Step 4. leave the rest filtrate to crystallize.

Copper (II) Oxide  {CuO (s)}  +  Dilute Sulfuric Acid {H2SO4 (aq)}   →  Copper (II) Sulphate {CuSO4 (s)}   +  Water {H2O}

4 0
3 years ago
A resting adult requires about 240 ml of pure oxygen/mind and breathes about 12 times every minute. if inhaled air contains 20 p
Dmitry_Shevchenko [17]

12 times breathe give 240 ml of pure O_{2}. Each breathe gives 20 ml of O_{2}.

Let us consider, volume of air per breathe= x ml.

Pure O_{2} from inhaled air= \frac{20}{100}x ml and Pure O_{2} from exhaled air= \frac{16}{100}x ml.

Pure O_{2} from inhaled and exhaled air= 20 ml

So, \frac{20}{100}x + \frac{16}{100}x = 20

Therefore, x = 55.5 ml

So, volume of air per breath= 55.5 ml.


7 0
3 years ago
Hydrazine, N2H4 , reacts with dinitrogen tetroxide, N204.
Virty [35]

Answer:

C

Explanation: thats what i got

3 0
3 years ago
If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol
Leviafan [203]

Answer:

V_{2} = 29.28\,L

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}

V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)

V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)

V_{2} = 29.28\,L

5 0
3 years ago
Cells in different tissues or organs (skin, eye, bone, etc.) contain different DNA. true or fasle,?
Ymorist [56]

Answer:

false

Explanation:

trust

6 0
3 years ago
Read 2 more answers
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