The average velocity of the whole journey will be total distance covered divided by the total time. It will be approximately equal to 8 m/s. The right answer is option B
<h2>VELOCITY</h2>
Velocity is the distance travelled in a specific direction. While the average velocity of the whole journey will be total distance covered divided by the total time
When driving a Toyota avensis car along a straight road for 16.5km at
50km/h,
The velocity = 50 km/h
Distance = 16.5 km
Use the speed formula to calculate time.
Speed = distance / time
Time = distance / speed
Time = 16.5 / 50
Time = 0.33 s
If over the next 20min, you walked another 2.5km further along the road for a petrol station, Then,
average velocity = Total distance covered divided by total time taken.
Where
The time t = 20/60 = 0.333 h
Total time = 0.33 + 0.3333
Total time = 0.6633333
Total distance = 16.5 + 2.5
Total distance = 19 km
Average velocity = 19 / 0.66333
Average Velocity = 28.64 km/h
Now convert Km/h to m/s
(28.6432 x 1000) / 3600
286432 / 3600
7.956m/s
Therefore, the average velocity of the whole journey from beginning of the drive to the arrival at the filling station will be approximately 8 m/s
Learn more about velocity here: brainly.com/question/6504879
Answer:
r=15.53 nm

Explanation:
Lets take electron is in between iron and uranium
Charge on electron
Charge on iron
Charge on uranium
We know that force between two charge

For equilibrium force between electron and iron should be force between electron and uranium
Lets take distance between electron and uranium is r so distance between electron and iron will be 37.5-r nm
Now by balancing the force

So r=15.53 nm
So force

Answer:
Approximately
(assuming that
.)
Explanation:
Let
denote the force that this spring exerts on the object. Let
denote the displacement of this spring from the equilibrium position.
By Hooke's Law, the spring constant
of this spring would ensure that
.
Note that the mass of the object attached to this spring is
. Thus, the weight of this object would be
.
Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus,
.
The spring in this question was stretched downward from its equilibrium by:
.
(Note that
is negative since this displacement points downwards.)
Rearrange Hooke's Law to find
in terms of
and
:
.
Answer:
Explanation:
The bead is moving on a vertical circular path so it must have a centripetal force towards the centre.
This force is equal to m v² / r
v is velocity of bead and r is radius of the circular path.
The vertical hoop is also rotating about a vertical axis passing through the centre at frequency f so the bead will experience a cetrifugal force due to rotation of the hoop. Its value is
m ω² r . Only at the point o degree and 180 degree , these forces are opposite to each other so at these points , the bead will be in equilibrium .
mv² / r = m ω² r
v² = ω² r²
v = ω r
= 2π f r
= 2 x 3.14 x 2 x 0.22
v = 2.76 m /s
For the bead to rise upto point θ = 90 degree , height achieved is radius R
required velocity = √ 2gR
= √ 2x 9.8x.22
= 2.076 m/s
This velocity is less than the velocity calculated earlier so the bead will be able to ride the required height.
v = 2.76 m/s
Answer:
b
Explanation:
radiation can treat tumors.