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coldgirl [10]
2 years ago
14

A cyclist rides at a constant speed of 4. 5 m/s around a curve. If the centripetal acceleration is 29 m/s2, what is the radius o

f the curve? 0. 16 m 0. 70 m 6. 4 m 34 m.
Physics
1 answer:
QveST [7]2 years ago
3 0

Answer:

a = v^2 / R = 4.5^2 / R = 29

R = 4.5^2 / 29 = .70 m

     

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Lighting a match results in light and heat. Since energy was not created by the match, what transformation took place?
Yuki888 [10]
Chemical energy stored in the compounds caked on the head of the match, and later the
chemical energy stored in the wood, was released in the form of heat and light when the
chemical compounds got hot enough.
3 0
3 years ago
An inventor claims to have invented a heat engine that receives 750kJ of heat from a source at 400K and produces 250kJ of net wo
IRISSAK [1]

Answer:

the claim is not valid or reasonable.

Explanation:

In order to test the claim we will find the maximum and actual efficiencies. maximum efficiency of a heat engine can be found as:

η(max) = 1 - T₁/T₂

where,

η(max) = maximum efficiency = ?

T₁ = Sink Temperature = 300 K

T₂ = Source Temperature = 400 K

Therefore,

η(max) = 1 - 300 K/400 K

η(max) = 0.25 = 25%

Now, we calculate the actual frequency of the engine:

η = W/Q

where,

W = Net Work = 250 KJ

Q = Heat Received = 750 KJ

Therefore,

η = 250 KJ/750 KJ

η = 0.333 = 33.3 %

η > η(max)

The actual efficiency of a heat engine can never be greater than its Carnot efficiency or the maximum efficiency.

<u>Therefore, the claim is not valid or reasonable.</u>

3 0
3 years ago
What is the magnitude of an electric field that balances the weight of a plastic sphere of mass 2.1 g that has been charged to -
Liula [17]

Answer:

Electric field, E=6.86\times 10^6\ N/C

Explanation:

It is given that,

Mass of sphere, m = 2.1 g = 0.0021 kg

Charge, q=-3\ nC=-3\times 10^{-9}\ C

We need to find the magnitude of electric field that balances the weight of a plastic spheres. So,

ma=qE

a = g

E=\dfrac{mg}{q}

E=\dfrac{0.0021\ kg\times 9.8\ m/s^2}{-3\times 10^{-9}\ C}

E=6860000\ N/C

or

E=6.86\times 10^6\ N/C

Hence, the magnitude of electric field that balances its weight is 6.86\times 10^6\ N/C. Hence, this is the required solution.

4 0
3 years ago
4. How much force is required to stop a 60 kg person traveling at 30 m/s during a time of a)
11111nata11111 [884]

Explanation:

F = ma, and a = Δv / Δt.

F = m Δv / Δt

Given: m = 60 kg and Δv = -30 m/s.

a) Δt = 5.0 s

F = (60 kg) (-30 m/s) / (5.0 s)

F = -360 N

b) Δt = 0.50 s

F = (60 kg) (-30 m/s) / (0.50 s)

F = -3600 N

c) Δt = 0.05 s

F = (60 kg) (-30 m/s) / (0.05 s)

F = -36000 N

3 0
4 years ago
A car travelling 95 km/h is 210 behind a truck travelling 75 km/h. how long will it take the care to reach the truck
masya89 [10]
<span>37.8 seconds First, determine the speed difference between the car and truck. 95 km/h - 75 km/h = 20 km/h Convert that speed into m/s to make a more convenient unit of measure. 20 km/h * 1000 m/km / 3600 s/h = 5.556 m/s Now it's simply a matter of dividing the distance between the two vehicles and their relative speed. 210 m / 5.556 m/s = 37.8 s So it will take 37.8 seconds for the car to catch the truck that's 210 meters in front of the car.</span>
5 0
3 years ago
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