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coldgirl [10]
2 years ago
14

A cyclist rides at a constant speed of 4. 5 m/s around a curve. If the centripetal acceleration is 29 m/s2, what is the radius o

f the curve? 0. 16 m 0. 70 m 6. 4 m 34 m.
Physics
1 answer:
QveST [7]2 years ago
3 0

Answer:

a = v^2 / R = 4.5^2 / R = 29

R = 4.5^2 / 29 = .70 m

     

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An airplane was moving 1200 km per minute traveling in a north-to-south direction when they were spotted by air traffic control.
Feliz [49]

Its velocity was 20 km/s southward

7 0
3 years ago
Read 2 more answers
2. An alternating current is represented by the equation I=20sin 100mt.
Sladkaya [172]

Explanation:

The general equation of an AC current is given by :

I=I_o sin\omega t

Where

I₀ is the peak value of current

\omega is angular frequency

As\ \omega=2\pi f

So,

f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{100\pi}{2\pi}\\\\f=50\ Hz

We know that,

I_{rms}=\dfrac{I_0}{\sqrt{2}}\\\\=\dfrac{20}{\sqrt{2}}\\\\I_{rms}=14.14\ A

So, the frequency is 50 Hz and the maximum rms value of current is 14.14 A.

3 0
2 years ago
A 34.0 kg sled is accelerated by a constant force of 45.0 N from 2.00 m/s to 16.00 m/s. For how long was the force acting on the
goblinko [34]

Answer: 10.6 sec

Explanation:

Because I got it right on my quiz :D

also because you can use the impulse momentum formula, Ft=m(triangle)v

so basically u do 16m/s-2m/s=14m/s and thats your triangle v (change in velocity) then multiply 14 times the mass, which is 34. Thats 476, so now you have ft=476, and you know F, the force, so all you have to do is divide 476 by 45, and you get like 10.5777777 which rounds up to 10.6!

4 0
3 years ago
In the decreasing order of magnitude, which of the following is correct?
Sergio [31]

Answer:

b. Static > sliding > rolling friction.

Explanation:

Static friction is greater than sliding friction.  It takes more force to get an object to start sliding than to keep it sliding.

Sliding friction is greater than rolling friction.  There are fewer points of contact for a round surface compared to a flat one.

5 0
3 years ago
When the driver presses the brake pedal, his car stops with an acceleration of - 8.7 m/s. How far will the car travel while comi
klemol [59]

Answer:

D. 5.7 m

Explanation:

The acceleration of the car is -8.7 m/s² and the car has an initial speed (u) of 10 m/s. The car said to come to rest, that means that the final velocity (v) of the car is 0 m/s.

To find the distance traveled by the car (s) before complete stop, this equation is being used:

v² = u² + 2as

2as=v^2-u^2\\s=\frac{v^2-u^2}{2a}\\ Substituting:\\s=\frac{0-10^2}{2*-8.7}\\ s=\frac{-100}{17.4}\\ s=5.7\ m

The car traveled 5.7 m before coming to a complete stop

3 0
3 years ago
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