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olya-2409 [2.1K]
3 years ago
8

How many atoms of copper in 3. 11 g of copper

Chemistry
1 answer:
son4ous [18]3 years ago
4 0
  • Atomic weight of copper = 63.5 g
  • 1 mole of copper contains = 63.5g = 6.023 × 10²³ atoms of copper
  • 1 g of copper contains
  • = \frac{ 6.023  \times  10²³}{63.5}= 9.4 × 10²¹ atoms
  • Therefore, 3.11g of copper contains
  • = 3.11 \times 9.4 \times  {10}^{21}  \\
  • = 29.234 × 10²¹ atoms

Hope you could get an idea from here.

Doubt clarification - use comment section.

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