Answer:
The metal will melt but their will be no change in temperature.
Explanation:
The metal is at its melting temperature which means it is still in solid phase but have to cross the enthalpy of its condensation at this same temperature to convert into liquid phase.
<u>On supplying heat, the metal's temperature will not change as the heat will be required as enthalpy of condensation to melt the solid to liquid at the melting temperature.</u>
Answer:
S1 = 1/2 g t^2 distance stone falls in time t
S2 = Vy t - 1/2 g t^2 distance thrown stone rises in time t
H = 49 = S1 + S2 = Vy t
t = 49 / 40 sec time when stones meet
Check:
Stone 1 falls: 1/2 g t^2 = 1/2 * 9.8 * (49 / 40)^2 = 7.35 m
Stone 2 rises : 40 * (49 / 40) - 1/2 * 9.8 (49 / 40)^2 = 41.65 m
there is a relation between intensity of light beam and the magnitude of electric field.<span>I=(1/2)c<span>ϵo</span>n<span>E2</span>=P/π<span>r2</span></span>
<span><span>E2</span>=2P/c<span>ϵo</span>nπ<span>r2</span></span>
E= magnitude of electric field
n= refractive index of medium
<span><span>μo</span><span>ϵ0</span>=1/<span>c2
</span></span>energy= power*time
= P*(1m/speed of light)<span><span>energy=(P∗1m)/c</span></span>
