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3 years ago

7

Is a roller coaster moving downhill is a potential or kinetic energy?

1 answer:

Sholpan [36]3 years ago

8 0

Hey there I see you need help well I am here to do just that, so your answer would be kinetic energy because potential energy is when her is sitting on the top of the hill so the<span> correct answer is :Kinetic Energy

Hope this helps if so why not hit that brainllest answer button ;)

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What is the starting and final energy for a battery?

EleoNora [17]

Electrical energy is the starting and final energy of a battery

8 0

3 years ago

A uniform 1.5-kg rod that is 0.80 m long is suspended at rest from the ceiling by two springs, one at each end of the rod. Both

leonid [27]

Answer:

θ=5.65°

Explanation:

Given Data

Mass m=1.5 kg

Length L=0.80 m

First spring constant k₁=35 N/m

Second spring constant k₂=56 N/m

To find

Angle θ

Solution

As the both springs take half load so apply Hooks Law:

Force= Spring Constant ×Spring stretch

F=kx

x=F/k

as

$d=x_{1}-x_{2}\\ as \\x=F/k\\so\\d=\frac{F_{1} }{k_{1}} -\frac{F_{2}}{k_{2}}\\ Where \\F=1/2mg\\d=\frac{(1/2)mg}{k_{1}} -\frac{(1/2)mg}{k_{2}}\\ d=\frac{mg}{2}(\frac{1}{k_{1}} -\frac{1}{k_{2}} )\\ And\\Sin\alpha=d/L\\\\alpha =sin^{-1}[\frac{mg}{2L}(1/k_{1}-1/k_{2})]\\\alpha =sin^{-1}[\frac{(1.5kg)(9.8m/s^{2} )}{2(0.80m)}(1/35Nm-1/56Nm) ]\\\alpha =5.65^{o}$

θ=5.65°

5 0

4 years ago

Light incident on a glass sheet is partly reflected and partly refracted. How is the reflected ray different from the refracted

kkurt [141]

Answer:

E. The refracted ray is vertically polarized whereas the reflected ray is horizontally polarized.

Explanation:

#PLATOLIVESMATTER

7 0

3 years ago

An unpolarized light with an intensity of 20W/m^2 is passed through a pair of polarizers. The first polarizer is set at an angle

bogdanovich [222]

Answer:

4.416 W/m²

Explanation:

Malus' law is given mathematically as

I = I₀ cos² θ

For the first polarizer, θ = 60°

I₁ = I₀ cos² 60°

I₁ = I₀ (0.5)² = 0.25I₀

For the second polarizer, θ = 20°

I₂ = I₁ cos² 20°

I₂ = I₁ (0.9397)² = 0.883 I₁

I₂ = 0.883 × 0.25I₀ = 0.2208 I₀

Note that

I₀ = 20 W/m²

I₂ = 0.2208 × 20 = 4.416 W/m²

Hope this Helps!!!

6 0

3 years ago

Ask Your Teacher The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s

adell [148]

Answer:

$\theta = 20\ rev$

Explanation:

Case 1

Given,

initial angular speed = 0 rev/s

final angular speed = 2 rev/s

time, t = 7 s

angular acceleration of the washer

$\alpha = \dfrac{\omega_f-\omega_i}{t}$

$\alpha = \dfrac{2-0}{7}$

$\alpha = 0.286\ rev/s^2$

using equation of rotational motion

$\omega_f^2 = \omega_i^2 + 2 \alpha \theta_1$

$2^2 = 0^2 + 2\times 0.286 \times \theta_1$

$\theta_1 = 7 rev$

Case 2

Given,

initial angular speed = 2 rev/s

final angular speed = 0 rev/s

time, t = 12 s

angular acceleration of the washer

$\alpha = \dfrac{\omega_f-\omega_i}{t}$

$\alpha = \dfrac{0-2}{13}$

$\alpha = -0.154\ rev/s^2$

using equation of rotational motion

$\omega_f^2 = \omega_i^2 + 2 \alpha \theta_2$

$0^2 = 2^2 + 2\times (-0.154) \times \theta_2$

$\theta_2 = 13 rev$

total revolution in this case

$\theta = \theta_1 + \theta_2$

$\theta =7 +13$

$\theta = 20\ rev$

total revolution of the washer is equal to 20 rev.

6 0

3 years ago