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timama [110]
3 years ago
7

Is a roller coaster moving downhill is a potential or kinetic energy?

Physics
1 answer:
Sholpan [36]3 years ago
8 0
Hey there I see you need help well I am here to do just that, so your answer would be kinetic energy because potential energy is when her is sitting on the top of the hill so the<span> correct answer is :Kinetic Energy 

Hope this helps if so why not hit that brainllest answer button ;)

</span>
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What is the starting and final energy for a battery?
EleoNora [17]
Electrical energy is the starting and final energy of a battery
8 0
3 years ago
A uniform 1.5-kg rod that is 0.80 m long is suspended at rest from the ceiling by two springs, one at each end of the rod. Both
leonid [27]

Answer:

θ=5.65°

Explanation:

Given Data

Mass m=1.5 kg

Length L=0.80 m

First spring constant k₁=35 N/m

Second spring constant k₂=56 N/m

To find

Angle θ

Solution

As the both springs take half load so apply Hooks Law:

Force= Spring Constant ×Spring stretch

F=kx

x=F/k

as

d=x_{1}-x_{2}\\  as \\x=F/k\\so\\d=\frac{F_{1} }{k_{1}} -\frac{F_{2}}{k_{2}}\\ Where \\F=1/2mg\\d=\frac{(1/2)mg}{k_{1}} -\frac{(1/2)mg}{k_{2}}\\ d=\frac{mg}{2}(\frac{1}{k_{1}} -\frac{1}{k_{2}} )\\ And\\Sin\alpha=d/L\\\\alpha =sin^{-1}[\frac{mg}{2L}(1/k_{1}-1/k_{2})]\\\alpha   =sin^{-1}[\frac{(1.5kg)(9.8m/s^{2} )}{2(0.80m)}(1/35Nm-1/56Nm) ]\\\alpha =5.65^{o}

θ=5.65°

5 0
4 years ago
Light incident on a glass sheet is partly reflected and partly refracted. How is the reflected ray different from the refracted
kkurt [141]

Answer:

E. The refracted ray is vertically polarized whereas the reflected ray is horizontally polarized.

Explanation:

#PLATOLIVESMATTER

7 0
3 years ago
An unpolarized light with an intensity of 20W/m^2 is passed through a pair of polarizers. The first polarizer is set at an angle
bogdanovich [222]

Answer:

4.416 W/m²

Explanation:

Malus' law is given mathematically as

I = I₀ cos² θ

For the first polarizer, θ = 60°

I₁ = I₀ cos² 60°

I₁ = I₀ (0.5)² = 0.25I₀

For the second polarizer, θ = 20°

I₂ = I₁ cos² 20°

I₂ = I₁ (0.9397)² = 0.883 I₁

I₂ = 0.883 × 0.25I₀ = 0.2208 I₀

Note that

I₀ = 20 W/m²

I₂ = 0.2208 × 20 = 4.416 W/m²

Hope this Helps!!!

6 0
3 years ago
Ask Your Teacher The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s
adell [148]

Answer:

\theta = 20\ rev

Explanation:

Case 1

Given,

initial angular speed = 0 rev/s

final angular speed = 2 rev/s

time, t = 7 s

angular acceleration of the washer

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{2-0}{7}

\alpha = 0.286\ rev/s^2

using equation of rotational motion

\omega_f^2 = \omega_i^2 + 2 \alpha \theta_1

2^2 = 0^2 + 2\times 0.286 \times \theta_1

\theta_1 = 7 rev

Case 2

Given,

initial angular speed = 2 rev/s

final angular speed = 0 rev/s

time, t = 12 s

angular acceleration of the washer

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{0-2}{13}

\alpha = -0.154\ rev/s^2

using equation of rotational motion

\omega_f^2 = \omega_i^2 + 2 \alpha \theta_2

0^2 = 2^2 + 2\times (-0.154) \times \theta_2

\theta_2 = 13 rev

total revolution in this case

\theta = \theta_1 + \theta_2

\theta =7 +13

\theta = 20\ rev

total revolution of the washer is equal to 20 rev.

6 0
3 years ago
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