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Elenna [48]
3 years ago
10

Nitrogen dioxide, NO2(g) (Delta. Hf = 33. 84 kJ/mol), is decomposed according to the following reaction: 2 upper N upper O subsc

ript 2 (g) right arrow upper N subscript 2 (g) plus 2 upper O subscript 2 (g). What is the enthalpy change when 2. 50 mol of nitrogen dioxide decomposes? Use Delta H r x n equals the sum of delta H f of all the products minus the sum of delta H f of all the reactants. 13. 5 kJ of energy released 13. 5 kJ of energy absorbed 84. 6 kJ of energy released 84. 6 kJ of energy absorbed.
Chemistry
1 answer:
quester [9]3 years ago
6 0

The heat of Reaction or Enthalpy is defined as the changes in the heat during a chemical reaction. The change in heat is calculated as the sum of all the heat change in products minus the sum of all the changes in the reactants.

<h3>How do you calculate the heat change in the reaction?</h3>

The chemical reaction between nitrogen and oxygen is given as:

\rm 2 N O_2 \rightarrow N_2 + 2 O_2\\\\&#10;\rm \Delta\; H_{f} &= 33.84 kJ/mol

Now, we know:

  • 1 mol Nitrogen dioxide requires = 33.84 kJ/mol
  • 2.50 mol of nitrogen oxide will give  = 33.84 \times 2.50
  • Energy released = 84.6 energy released

Thus, the enthalpy change for the reaction will be 84.6 energy released.

Learn more about enthalpy change here:

brainly.com/question/25912483

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