300 milliliter a of NaOH solution would contain of NaOH
<u>Solution:</u>
Given volume percentage = Weight of solute =
Consider,
Therefore, the answer is 300 ml.
Please see the pic, I'd solved in it..
Answer:
0.544 eV; Ag is a smaller atom.
Explanation:
1. Ionization energy of hydrogen
The outermost electrons in Rb and Ag are in 5s orbitals.
The formula for the energy of an electron in a hydrogen atom is
E = -13.6/n² eV
For a hydrogen atom in a 5s orbital,
E = -13.6/5² = -13.6/25 = -0.544 eV
The ionization energy would be 0.544 eV.
2. Rb vs Ag
The first electrons to be removed from Rb and Ag are in 5s orbitals.
The atomic radius of Ag is less than that of Rb because, as you go from left to right across the Row, you are adding 10 protons to the nucleus and 10 electrons to the outer shell.
The added electrons do not effectively shield each other from the attraction of the nucleus, so the 5s electron of Ag is closer in.
It takes more energy to remove the electron from silver, so the ionization energy of Ag is greater than that of Rb.
Rip bro but I need the point
Answer is: the osmotic pressure of aqueous solution of sucrose is 6.032 atm.<span>
c(C</span>₁₂H₂₂O₁₁) = 0.237 mol/L; concentration of solution.
T(C₁₂H₂₂O₁₁) = 37°C = 310.15 K; temperature in Kelvins.
R = 0.08206 L·atm/mol·K; universal gas constant.
π = c(C₁₂H₂₂O₁₁) · T(C₁₂H₂₂O₁₁) · R.
π = 0.237 mol/L · 310.15 K · 0.08206 L·atm/mol·K.
π = 6.032 atm · 101.325 kPa/atm = 611.2 kPa