All categories

2 years ago

even though the sun is so much bigger than the moon, why does the moon have a stronger effect on tides?

Physics

1 answer:

anygoal [31]2 years ago

5 0

Answer:

the moon is closer to the earth so that its gravitational gradient is stronger than that of the sun.

Explanation:

You might be interested in

A car is traveling south is 200 kilometers from it’s starting point after 2 hours. What is the average velocity of the car

Lesechka [4]

Answer:

100

Explanation:

take note that v=d/t (velocity is distance over(divided by) time, so in this case it would be 200 (distance) divided by 2 (time) = 100

6 0

3 years ago

The PV system is operating in a location where the annual average daily incident solar energy (the insolation) on the array equa

vlabodo [156]

The average amount of solar energy incident on the PV per day is 10000 kWh/day.

<h3>Equation</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let the PV array has an area equal to 50 square meters. Hence:

Average amount of solar energy incident on the PV per day = 200 kWh/m²/day * 50 m² = 10000 kWh/day.

Find out more on Equation at: brainly.com/question/2972832

5 0

2 years ago

A centripetal force causes circular motion because it accelerates an object

MAVERICK [17]

The answer is option A.

Centripetal force is always directed towards the centre and does not change the speed of the body,but there is a change in the direction.

6 0

3 years ago

Read 2 more answers

Two polarizers A and B are aligned so that their transmission axes are vertical and horizontal, respectively. A third polarizer

Reptile [31]

Answer:

Explanation:

Let the angle between the first polariser and the second polariser axis is θ.

By using of law of Malus

(a)

Let the intensity of light coming out from the first polariser is I'

$I' = I_{0}Cos^{2}\theta$ .... (1)

Now the angle between the transmission axis of the second and the third polariser is 90 - θ. Let the intensity of light coming out from the third polariser is I''.

By the law of Malus

$I'' = I'Cos^{2}\left ( 90-\theta \right )$

So,

$I'' = I_{0}Cos^{2}\theta Cos^{2}\left ( 90-\theta \right )$

$I'' = I_{0}Cos^{2}\theta Sin^{2}\theta$

$I'' = \frac{I_{0}}{4}Sin^{2}2\theta$

(b)

Now differentiate with respect to θ.

$I'' = \frac{I_{0}}{4}\times 2 \times 2 \times Sin2\theta \times Cos 2\theta$

$I'' = \frac{I_{0}}{2}\times Sin 4\theta$

7 0

3 years ago

The greatest pull of a magnet is near its poles.<br><br> True<br> False

DIA [1.3K]

False because opposites attract. :)

6 0

2 years ago

Read 2 more answers