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eimsori [14]
3 years ago
15

What is the sixth term in the series; 6, 12, and 18? ​

Mathematics
2 answers:
Studentka2010 [4]3 years ago
8 0

Answer:

from this you can see that they add 6 each time so

6+6+6+6+6+6

36

Hope This Helps!!!

MAXImum [283]3 years ago
5 0
The sixth term is 36 because it is counting by 6
6x6=36
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if a toy rocket is launced vertically upward from ground level with an inital velocity of 128 feet per second, then its high h,
makkiz [27]
The toy rocket hits the ground when h(t) = 0.
So, h(t) = 0 = -9t^2 + 81.

Solving the equation,
-9t^2 = -81
Dividing by -9
t^2 = 9
Taking the square root.
t = 3

The answer is 3 seconds.
7 0
3 years ago
Select the correct answer.
Alexeev081 [22]

Answer: B

Step-by-step explanation:

8 0
3 years ago
for events A and B, P(A)= 3/14 and P(B)= 1/5. Also, P(A and B)= 3/65. Are A and B independent events?
Lady_Fox [76]

No, A and B are not independent events

Step-by-step explanation:

Let us study the meaning independent probability  

  • Two events are independent if the result of the second event is not  affected by the result of the first event
  • If A and B are independent events, the probability of both events  is the product of the probabilities of the both events  P (A and B) = P(A) · P(B)

∵ P(A) = \frac{3}{14}

∵ P(B) = \frac{1}{5}

∴ P(A) . P(B) = \frac{3}{14} × \frac{1}{5}

∴ P(A) . P(B) = \frac{3(1)}{14(5)}

∴ P(A) . P(B) = \frac{3}{70}

∵ P(A and B) = \frac{3}{65}

∵ P(A) . P(B) = \frac{3}{70}

- The two answers are not equal

∴ P (A and B) ≠ P(A) · P(B)

- In independent events P (A and B) = P(A) · P(B)

∴ A and B are not independent events

No, A and B are not independent events

Learn more:

You can learn more about probability in brainly.com/question/13053309

#LearnwithBrainly

5 0
3 years ago
A car passes a landmark traveling at a constant rate of 55 kilometers per hour. One hour later, a second car passes the same lan
yarga [219]
Recall your d = rt, distance = rate * time

one car is going at 55kph, at say hmmm "t" time
the second car zooms by at 75kph, an hour later, thus " t + 1 "

notice, overtaking the 1st car, simply means, the second car comes from behind approaches the first car from behind and "gets there", at that very second, both cars have travelled a distance, say "d"

if the first car travelled "d" kilometers
for the second car to "get there" has to had travelled "d" distance as well

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{first car}&d&55&t\\
\textit{second car}&d&75&t+1
\end{array}
\\\\\\
\begin{cases}
d=55t\\
d=75(t+1)\\
-------\\
55t=75(t+1)
\end{cases}

solve for "t"
7 0
3 years ago
Read 2 more answers
Each question on a multiple-choice exam has four choices. One of the choices is correct, worth four points. Another choice is wr
kifflom [539]

Answer:A)0.75

Step-by-step explanation:

Given

There are four options to a question

out of which one is correct with 4 points

one is wrong but carries 1 point

Other two are wrong with a negative Point

Probability of selecting an option is \frac{1}{4}

Expected score=\frac{1}{4}\times 4+\frac{1}{4}\times 1+\frac{1}{4}\times (-1)+\frac{1}{4}\times (-1)

Expected score=1+0.25-0.5

Expected score=0.75

8 0
3 years ago
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