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3 years ago

Water is the only pure substance that exists as a liquid at normal Earth temperatures.

1 answer:

4 0

Here are many things that exist as liquid at "normal" Earth temperatures. I would bet that you've seen a demonstration or someone use something with liquid mercury.

<span>FALSE </span>

<span>Hope this helps.</span>

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Leticia leaves the grocery store

Volgvan

Answer:

what am i suppose to answer o.o

Explanation:

7 0

3 years ago

Read 2 more answers

Find the speed of a satellite in a circular orbit around the Earth with a radius 3.57 times the mean radius of the Earth. (Radiu

nignag [31]

Answer: The speed of a satellite in a circular orbit around the Earth with a radius 3.57 times the mean radius of the Earth is 4188.11 m/s.

Explanation: To find the answer, we need to know about the equation of motion of a satellite around earth.

<h3>What is the equation of motion of a satellite around earth?</h3>

We have gravitational force of attraction between the satellite of mass m and earth of mass M as,

$F_g=\frac{GMm}{r^2}$

The expression for centripetal force of,

$F_c=\frac{mv^2}{r} \\$

These two forces are equal for a satellite around earth.

$\frac{GMm}{r^2} =\frac{mv^2}{r} \\thus,\\v=\sqrt{\frac{GM}{r} }$

<h3>How to solve the problem?</h3>

Given that,

$r=3.57 R_E=3.57*6.37*10^3=22.74*10^3 km\\M=5.98*10^24kg\\G=6.67*10^{-11}Nm^2/kg^2$

Thus, the speed of the satellite will be,

$v=\sqrt{\frac{6.67*10^{-11}*5.98*10^{24}}{22.74*10^6m} } =4188.11 m/s$

Thus, we can conclude that the speed of satellite will be 4188.11 m/s.

Learn more about motion of satellites here:

brainly.com/question/28105737

#SPJ4

4 0

2 years ago

Read 2 more answers

velikii [3]

Answer:

The correct solution is option A "10 meters".

Explanation:

The given values are:

Wave X,

Frequency,

$F_x=200 \ H_z$

Wavelength

$\lambda_x=35 \ m$

Wave Y,

Frequency,

$F_y=700 \ Hz$

Let its wavelength = $\lambda_y$

As we know,

⇒ $v=f \lambda$

For both waves, medium is same then

⇒ $v_x=v_y$

⇒ $f_x \lambda_x=f_y \lambda_y$

then,

⇒ $\lambda_y=\frac{f_x \lambda_x}{f_y}$

On substituting the estimated values in the above equation, we get

⇒ $=\frac{200\times 35}{700}$

⇒ $=\frac{7000}{700}$

⇒ $=10 \ m$

4 0

3 years ago

The potential difference between the plates of a parallel plate capacitor is 4.00 V. If the plate separation for this capacitor

shtirl [24]

<h2>Answer:</h2>

66.67 V / m

<h2>Explanation:</h2>

The electric field intensity (E) between the plates of a capacitor is the ratio of the potential difference (V) between the plates to the distance (d) of separation between the plates. Electric field intensity can be measured in V/m. It can be written as follows;

E = V / d ----------------------------(i)

<em>From the question;</em>

V = 4.00V

d = 6.00cm = 0.06m

<em>Substitute these values into the equation above. i.e equation (i) as follows;</em>

E = 4.00 / 0.06

E = 66.67 V / m

Therefore, the electric field intensity between the plates of the capacitor is 66.67 V / m

4 0

3 years ago

If the speed of sound is approximately 671 mi/hr, about how many meters per second is it? (1mile=1609m)

zzz [600]

671mi/hr

= 671/60min (calculates miles/min)
= (671/60) ÷ 60seconds (calculates miles/sec)

((671/60) ÷ 60)× 1609m
= 299.899 meters/sec
= 299.90m (round off to 2 decimals )

3 0

3 years ago