weather is like corono everywhere #stay safe
Answer:
82.62%
Explanation:
The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
![z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean\ and\ \sigma=standard\ deviation.\\\\Given \ that\ \mu=12V, \sigma=0.11V.\\\\For\ x11.85V:\\\\z=\frac{11.85-12}{0.11} =-1.36\\\\](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%20%5C%5C%5C%5Cwhere%5C%20x%3Draw%5C%20score%2C%5Cmu%3Dmean%5C%20and%5C%20%5Csigma%3Dstandard%5C%20deviation.%5C%5C%5C%5CGiven%20%5C%20that%5C%20%5Cmu%3D12V%2C%20%5Csigma%3D0.11V.%5C%5C%5C%5CFor%5C%20x%3C12.15V%3A%5C%5C%5C%5Cz%3D%5Cfrac%7B12.15-12%7D%7B0.11%7D%20%3D1.36%5C%5C%5C%5CFor%5C%20x%3E11.85V%3A%5C%5C%5C%5Cz%3D%5Cfrac%7B11.85-12%7D%7B0.11%7D%20%3D-1.36%5C%5C%5C%5C)
From the normal distribution table, P(11.85 < x < 12.15) = P(-1.36 < z < 1.36) = P(z < 1.36) - P(z < -1.36) = 0.9131-0.0869 = 0.8262 = 82.62%
Answer:
The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.
Explanation:
Power is the rate of change of work in time, since given input is average power, the total energy (
) of the motor of the electric vehicle, measured in joules, is determined by this formula:
![\Delta E = \dot W \cdot \Delta t](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20%5Cdot%20W%20%5Ccdot%20%5CDelta%20t)
Where:
- Average power, measured in watts.
- Time, measured in seconds.
Now, let convert average power and time into watts and seconds, respectively:
Average Power
![\dot W = (50\,hp)\times \frac{746\,W}{1\,hp}](https://tex.z-dn.net/?f=%5Cdot%20W%20%3D%20%2850%5C%2Chp%29%5Ctimes%20%5Cfrac%7B746%5C%2CW%7D%7B1%5C%2Chp%7D)
![\dot W = 3.730\times 10^{4}\,W](https://tex.z-dn.net/?f=%5Cdot%20W%20%3D%203.730%5Ctimes%2010%5E%7B4%7D%5C%2CW)
Time
![\Delta t = (1\,h)\times \frac{3600\,s}{1\,h} + (25\,min)\times \frac{60\,s}{1\,min}](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20%281%5C%2Ch%29%5Ctimes%20%5Cfrac%7B3600%5C%2Cs%7D%7B1%5C%2Ch%7D%20%2B%20%2825%5C%2Cmin%29%5Ctimes%20%5Cfrac%7B60%5C%2Cs%7D%7B1%5C%2Cmin%7D)
![\Delta t = 5.100\times 10^{3}\,s](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%205.100%5Ctimes%2010%5E%7B3%7D%5C%2Cs)
Then, the total energy is:
![\Delta E = (3.730\times 10^{4}\,W)\cdot (5.100\times 10^{3}\,s)](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20%283.730%5Ctimes%2010%5E%7B4%7D%5C%2CW%29%5Ccdot%20%285.100%5Ctimes%2010%5E%7B3%7D%5C%2Cs%29)
![\Delta E = 1.902\times 10^{8}\,J](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%201.902%5Ctimes%2010%5E%7B8%7D%5C%2CJ)
The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.
:nanjan lang din yan sa binasa mo ne........
Answer:
t=5.5 mm
Heat dissipation per unit length = 90.477 W/m
Explanation:
Given that
Diameter d = 5 mm ⇒r = 2.5 mm
Conductivity of insulated material K = 0.16 W/mK
Heat transfer coefficient = 20 ![\frac{W}{m^2K}](https://tex.z-dn.net/?f=%5Cfrac%7BW%7D%7Bm%5E2K%7D)
When thickness reaches up to critical radius of insulation then heat dissipation will be maximum
We know that critical radius of insulation of wire is given as follow
![r_{c}=\dfrac{K_{insulation}}{h_{surrounding}}](https://tex.z-dn.net/?f=r_%7Bc%7D%3D%5Cdfrac%7BK_%7Binsulation%7D%7D%7Bh_%7Bsurrounding%7D%7D)
Now by putting the values
![r_{c}=\dfrac{0.16}{20}](https://tex.z-dn.net/?f=r_%7Bc%7D%3D%5Cdfrac%7B0.16%7D%7B20%7D)
![r_{c}=8 mm](https://tex.z-dn.net/?f=r_%7Bc%7D%3D8%20mm%20)
So the thickness of insulation
t=8-2.5 mm
t=5.5 mm
As we know that heat transfer due to convection given as follows
Q = hAΔ T
Q=20 x 2 x π x 0.008 x (120-30)
Q = 90.477 W/m
So heat dissipation per unit length = 90.477 W/m