Answer:
Option ‘a’ is the cheapest for this house.
Explanation:
Cheapest method of heating must have least cost per kj of energy. So, convert all the energy in the same unit (say kj) and take select the cheapest method to heat the house.
Given:
Three methods are given to heat a particular house are as follows:
Method (a)
Through Gas, this gives energy of amount $1.33/therm.
Method (b)
Through electric resistance, this gives energy of amount $0.12/KWh.
Method (c)
Through oil, this gives energy of amount $2.30/gallon.
Calculation:
Step1
Change therm to kj in method ‘a’ as follows:
$/kj.
Step2
Change kWh to kj in method ‘b’ as follows:
$/kj.
Step3
Change kWh to kj in method ‘c’ as follows:
$/kj.
Thus, the method ‘a’ has least cost as compare to method b and c.
So, option ‘a’ is the cheapest for this house.
Answer:crane and engine I guess
Explanation:
Answer:
Power = 371.28 kW
Explanation:
Initial pressure, P1 = 5 bar
Final pressure, P2 = 1 bar
Initial temperature, T1 = 320°C
Final temperature, T2 = 160°C
Volume flow rate, V = 0.65m³/s
From steam tables at state 1,
h1 = 3105.6 kJ/kg, s1 = 7.5308 kJ/kgK
v1 = 0.5416 m³/kg
Mass flow rate, m = V/v1
m = 1.2 kg/s
From steam tables, at state 2
h2 = 2796.2 kJ/kg, s2 = 7.6597 kJ/kgK
Power developed, P = m(h1 - h2)
P = 1.2(3105.6-2796.2)
P = 371.28 kW