All categories

3 years ago

What is the centripetal force acting on a 1.5 kg mass moving in a circular path with a centripetal

Physics

1 answer:

zloy xaker [14]3 years ago

8 0

The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N

A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.

According to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.

The centripetal force is the external force at work here and It's the net force that propels the object in a circular motion.

Using the formula for calculating centripetal force:

$\mathbf{F_c = mass (m) \times acceleration (a)}$

$\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}$

$\mathbf{F_c = 27 \ N}$

Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

You might be interested in

Twenty- four specific objects transmit complex radio codes, including time signals traveling at the speed of light. You can cont

Mademuasel [1]

Answer:

GPS Satellites.

Explanation:

You will always be able to have access to 4 of them no matter where you are on the Earth. This is useful for triangulation.

7 0

3 years ago

A driver notices an upcoming speed limit change from 45 mi/h (20 m/s) to 25 mi/h (11 m/s). If she estimates

zloy xaker [14]

Answer:

-2.79 m/s²

Explanation:

Given:

v₀ = 20 m/s

v = 11 m/s

Δx = 50 m

Find: a

v² = v₀² + 2aΔx

(11 m/s)² = (20 m/s)² + 2a (50 m)

a = -2.79 m/s²

Round as needed.

8 0

4 years ago

3. 5 m A D с B 0.5 m 1.3 m Figure 2 A beam ADCB has length 5 m. The beam lies on a horizontal step with the end A on the step an

alukav5142 [94]

Based on the principle of moments and the data provided;

the mass of the rod is 20 kg
the smallest value of X of the block that will keep the rod in equilibrium will be 4.054 kg

<h3>What is the principle of moments?</h3>

The principle of moments states that the for a body in equilibrium, the sum of the clockwise moments is equal to the sum of the anticlockwise moments about a point.

Sum of Clockwise moments = Sum of Anticlockwise moments
Moment of a force = mass × perpendicular distance.

At the point where the uniform rod is about to tilt, it is at equilibrium.

Anticlockwise moments = 30 × (1.3 - 0.5) = 24

Clockwise moments = m × (2.5 - 1.3)

where m is the mass of the end

Clockwise moments = m × 1.2

1.2 × m = 24

m = 20 Kg

Therefore, the mass of the rod is 20 kg

Assuming the boy moves to B and a block of mass X is placed at:

Anticlockwise moments = 30 × 1.3 = 39

Clockwise moments = 20 × 1.2 + X × 3.7

Clockwise moments = 24 + 3.7X

39 = 24 + 3.7X

3.7X = 15

X = 4.054 kg

Therefore, the smallest value of X of the block that will enable the boy to stand on the beam at B without the beam tilting is 4.054 kg

Assuming that the block is a particle allowed the assumption that the block touches the rod at only a point.

Learn more about principle of moments at: brainly.com/question/26117248

8 0

2 years ago

A tall cylinder with a cross-sectional area 13.0 cm2 is partially filled with mercury; the surface of the mercury is 6.00 cm abo

kvv77 [185]

Answer:

V = 1060.8 cm³

Explanation:

we know that the pressure,

P = density x gravity x depth

ρm is the density of mercury

ρw is the density of water

the pressure due to mercury P₁= (ρm) g h₁

the pressure due to water P₂ = (ρw) g h₂

the total pressure

P = P₁ + P₂

P = (ρm) g h₁ + (ρw) g h₂

but the total pressure is double the pressure due to mercury.

(ρm) g h₁ =(ρw) g h₂

$h_2 = \dfrac{\rho_m\times h_1}{\rho_w}$

$h_2 =13.6\times 6$

h₂ = 81.6 cm

the height of the water is 81.6 cm

the volume

V = height x area

V = 81.6 x 13

V = 1060.8 cm³

the volume of water must be added to double the gauge pressure is V = 1060.8 cm³

8 0

3 years ago

A 50 Ohm resistance causes a current of 5 milliamps to flow through a circuit connected to a battery. What is the power in the c

UkoKoshka [18]

Answer:0.00125 watts

Explanation:

resistance=50 ohms

Current=5 milliamps

Current=5/1000 milliamps

Current =0.005 amps

power=(current)^2 x (resistance)

Power=(0.005)^2 x 50

Power=0.005 x 0.005 x 50

Power=0.00125 watts

8 0

3 years ago

Read 2 more answers