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alexira [117]
2 years ago
11

3. This material is considered flammable.

Engineering
2 answers:
almond37 [142]2 years ago
4 0

Answer:

All of the above

Explanation:

Most of materials are flammable because of the chemicals theyre made up of.  Most materials that are bought say to keep them at room temature for a reason.

Ray Of Light [21]2 years ago
4 0

I'm not sure try oil

hoped I helped!

Have a wonderful day-

Bye!

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CS3733: Homework/Practice 05 Suppose we would like to write a program called monitor which allows two other programs to communic
valina [46]

Answer:

#include<stdio.h>

#include<stdlib.h>

#include<unistd.h>

#include<sys/types.h>

#include<string.h>

#include<pthread.h>

//#include<sys/wait.h>

int main(int argc, char** argv)

{

int fd1[2];

int fd2[2];

int fd3[2];

int fd4[2];

char message[] = "abcd";

char input_str[100];

pid_t p,q;

if (pipe(fd1)==-1)

{

 fprintf(stderr, "Pipe Failed" );

 return 1;

}

if (pipe(fd2)==-1)

{

 fprintf(stderr, "Pipe Failed" );

 return 1;

}

if (pipe(fd3)==-1)

{

 fprintf(stderr, "Pipe Failed" );

 return 1;

}

if (pipe(fd4)==-1)

{

 fprintf(stderr, "Pipe Failed" );

 return 1;

}

p = fork();

if (p < 0)

{

 fprintf(stderr, "fork Failed" );

return 1;

}

// child process-1

else if (p == 0)

{

 close(fd1[0]);// Close reading end of first pipe

 char concat_str[100];

 printf("\n\tEnter meaaage:"):

 scanf("%s",concat_str);

 write(fd1[1], concat_str, strlen(concat_str)+1);

 // Concatenate a fixed string with it

 int k = strlen(concat_str);

 int i;

 for (i=0; i<strlen(fixed_str); i++)

 {

  concat_str[k++] = fixed_str[i];

 }

 concat_str[k] = '\0';//string ends with '\0'

 // Close both writting ends

 close(fd1[1]);

 wait(NULL);

//.......................................................................

 close(fd2[1]);

 read(fd2[0], concat_str, 100);

 if(strcmp(concat_str,"invalid")==0)

 {

 printf("\n\tmessage not send");

 }

 else

 {

  printf("\n\tmessage send to prog_2(child_2).");

 }

 close(fd2[0]);//close reading end of pipe 2

 exit(0);

}

else

{

 close(fd1[1]);//Close writting end of first pipe

 char concat_str[100];

 read(fd1[0], concal_str, strlen(concat_str)+1);

 close(fd1[0]);

 close(fd2[0]);//Close writing end of second pipe

 if(/*check if msg is valid or not*/)

 {

  //if not then

  write(fd2[1], "invalid",sizeof(concat_str));

  return 0;

 }

 else

 {

  //if yes then

  write(fd2[1], "valid",sizeof(concat_str));

  close(fd2[1]);

  q=fork();//create chile process 2

  if(q>0)

  {

   close(fd3[0]);/*close read head offd3[] */

   write(fd3[1],concat_str,sizeof(concat_str);//write message by monitor(main process) using fd3[1]

   close(fd3[1]);

   wait(NULL);//wait till child_process_2 send ACK

   //...........................................................

   close(fd4[1]);

   read(fd4[0],concat_str,100);

   close(fd4[0]);

   if(sctcmp(concat_str,"ack")==0)

   {

    printf("Messageof child process_1 is received by child process_2");

   }

   else

   {

    printf("Messageof child process_1 is not received by child process_2");

   }

  }

  else

  {

   if(p<0)

   {

    printf("Chiile_Procrss_2 not cheated");

   }

   else

   {

     

    close(fd3[1]);//Close writing end of first pipe

    char concat_str[100];

    read(fd3[0], concal_str, strlen(concat_str)+1);

    close(fd3[0]);

    close(fd4[0]);//Close writing end of second pipe

    write(fd4[1], "ack",sizeof(concat_str));

     

   }

  }

 }

 close(fd2[1]);

}

}

8 0
3 years ago
A shunt regulator utilizing a zener diode with an incremental resistance of 8 ohm is fed through an 82-Ohm resistor. If the raw
spayn [35]

Answer:

\triangle V_0=0.08V

Explanation:

From the question we are told that:

Incremental resistance  R=8ohms

Resistor Feed R_f=82ohms

Supply Change \triangle V=1

Generally the equation for  voltage rate of change is mathematically given by

 \frac{dV_0}{dV}=\frca{R}{R_1r_3}

Therefore

 \triangle V_0=\triangle V*\frac{R}{R_fR}

 \triangle V_0=1*\frac{8}{8*82}

 \triangle V_0=0.08V

7 0
3 years ago
Describe how you could engineer the situation to produce even more friction and heat
lana66690 [7]
True the use many abstract power
6 0
2 years ago
Why is apartments called apartments but there not apart???
Lisa [10]

Answer:

he word Apartment derives from the French apartment. ... An apartment came to be called so because it has individual/private rooms for different people, on the same floor. These rooms were, of course, apart. In Britain, apartments are called "flats", as everyone knows.

Explanation:

4 0
3 years ago
Read 2 more answers
(1) Prompt the user for the number of cups of lemon juice, water, and agave nectar needed to make lemonade. Prompt the user to s
Lady bird [3.3K]

Answer:

The program to this question as follows:

Program:

Lemon= float(input('Enter lemon juice value in cups: ')) #defining float variable and input value by user

Water= float(input('Enter water value in cups: ')) #defining float variable and input value by user

Agave= float(input('Enter agave nectar value in cups: ')) #defining float variable and input value by user

Serve= float(input('enter serving value: '))  #defining float variable and input value by user

print ('Lemonade ingredients - yields',Serve,'servings',) #print value

print (Lemon,'cups in lemon juice',) #print value

print (Water,'cups in water',) #print value

print (Agave,'cups in agave nectar',) #print value

Output:

Enter lemon juice value in cups: 2

Enter water value in cups: 3

Enter agave nectar value in cups: 2

enter serving value: 2

Lemonade ingredients - yields 2.0 servings

2.0 cups in lemon juice

3.0 cups in water

2.0 cups in agave nectar

Explanation:

In the above python code, four float variable "Lemon, Water, Agave, and Serve" is defined, which is the input function is used.  

  • The input function message is written that passes in function parameter, that accepts value in the above variables.  
  • In the next step, the print function is used, which prints the above user input values.
6 0
3 years ago
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