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11Alexandr11 [23.1K]
2 years ago
6

A 30.g sample of Al(s) is heated to 50°C and placed in a calorimeter containing 150g of water at 20°C. As the system approaches

thermal equilibrium, energy is transferred
from the Al(s) to the water and the temperature of the water decreases

Answer A: from the A l, solid to the water and the temperature of the water decreases
A

from the Al(s) to the water and the temperature of the Al(s) decreases

Answer B: from the A l, solid to the water and the temperature of the A l, solid decreases
B

from the water to the Al(s) and the temperature of the water increases

Answer C: from the water to the A l, solid and the temperature of the water increases
C

from the water to the Al(s) and the temperature of the Al(s) increases
Chemistry
1 answer:
SpyIntel [72]2 years ago
5 0

Energy is transferred from the Al (solid) to water and the temperature of the water increases while the temperature of the Al (solid) decreases.

<h3>Heat energy</h3>

Heat energy is a form of energy transferred from one body to another due to a temperature difference between the bodies.

Heat energy is also known as thermal energy.

In heat transfer, heat is transferred from a body at higher temperature to a body at lower temperature.

In the heat transfer between the heated aluminium and the water, the solid aluminium is at a higher temperature than the water, hence, heat energy is transferred from the aluminium to water.

Therefore heat energy is transferred from the Al (solid) to water and the temperature of the water increases while the temperature of the Al (solid) decreases.

Learn more about about heat transfer at: brainly.com/question/12072129

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Answer:

Genetic equilibrium is the state in which allele frequencies do

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Explanation:

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What is the SI unit for volume?
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The SI unit for volume is cubic meters of M^3

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How is the molarity affected if some solution splashes out of the flask during titration?
Jobisdone [24]

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not affected?

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3 years ago
What is the balanced equation if electrolysis?​
ra1l [238]

Answer:

It's Al 3+ + 3e - → Al

Explanation:

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5 0
2 years ago
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What volume in milliliters of 1.420 M sulfuric acid is needed to neutralize 3.209 g of aluminum hydroxide 3 H 2 SO 4 (aq)+2 Al(O
nadya68 [22]

Answer:

V=43.46mL

Explanation:

Hello!

In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

n_{H_2SO_4}=3.209gAl(OH)_3*\frac{1molAl(OH)_3}{78.00gAl(OH)_3} *\frac{3molH_2SO_4}{2molAl(OH)_3} \\\\n_{H_2SO_4}=0.0617molH_2SO_4

Then, given the molarity, it is possible to obtain the milliliters as follows:

V=\frac{n}{M}=\frac{0.0617mol}{1.420mol/L}*\frac{1000mL}{1L}\\\\V=43.46mL

Best regards!

7 0
3 years ago
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