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snow_lady [41]
3 years ago
8

What mistake did Farah make in this experiment? Farah conducted the following experiment to check whether fabrics of different c

olours take different times to dry. She took one piece each of red, white and blue cotton. They were all of the same size and quality. She wet each piece with the same amount of water and hung them from spring balances near a fan as shown above. She noted the weight of each piece of cotton. She then put the fan on and noted the weight of each piece of cotton at the end of every two minutes. The weight of all the pieces of cotton decreased as water evaporated from the them.​
Physics
1 answer:
Cerrena [4.2K]3 years ago
3 0
She hung up the pieces of cotton BEFORE putting the fan on, also the water evaporating can take longer or shorter even if they are all the same :))
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What are gamma rays and what are its uses??<br>​
sukhopar [10]

"Gamma rays" is the name that we call the shortest of all electromagnetic waves.  They're shorter than radio waves, microwaves, infrared waves, heat waves, visible light waves, ultraviolet waves, and X-rays.  They extend all the way down to waves that are as short as the distance across an atom.

Being so short, they carry lots of energy.  They can penetrate many materials, and they can damage living cells and DNA.  They're dangerous.

The sun puts out a lot of gamma radiation.  The atmosphere (air) filters out a lot of it, otherwise there couldn't even be any life on Earth.  

As soon as astronauts fly out of the atmosphere, they need a lot of shielding from gamma rays.

You know the precautions we take when we're around X-rays.  The same precautions apply around gamma rays, only a lot more so.

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3 0
3 years ago
Is being a plat 2 in rainbow 6 siege a good rank?
icang [17]

Answer:

In a way it does, but overall, there are many factors that affect your rank. In general, and talking about the average Platinum II, they are pretty decent according to casual player standards.

Explanation:

6 0
3 years ago
(a) If a proton with a kinetic energy of 6.2 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.5
Tju [1.3M]

Answer:

The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

Explanation:

Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}

Given that,

Kinetic energy = 6.2 MeV

Radius = 0.500 m

We need to calculate the acceleration

Using formula of acceleration

a=\dfrac{v^2}{r}

Put the value into the formula

a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}

Put the value into the formula

a=\dfrac{6.2\times10^{6}\times1.6\times10^{-19}}{\dfrac{1}{2}\times1.67\times10^{-27}\times0.51}

a=2.32\times10^{15}\ m/s^2

We need to calculate the rate at which it emits energy because of its acceleration is

\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}

Put the value into the formula

\dfrac{dE}{dt}=\dfrac{(1.6\times10^{-19})^2\times(2.3\times10^{15})^2}{6\pi\times8.85\times10^{-12}\times(3\times10^{8})^3}

\dfrac{dE}{dt}=3.00\times10^{-23}\ J/s

The energy in ev/s

\dfrac{dE}{dt}=\dfrac{3.00\times10^{-23}}{1.6\times10^{-19}}\ J/s

\dfrac{dE}{dt}=1.875\times10^{-4}\ ev/s

We need to calculate the fraction of its energy that it radiates every second

\dfrac{\dfrac{dE}{dt}}{E}=\dfrac{1.875\times10^{-4}}{6.2\times10^{6}}

\dfrac{\dfrac{dE}{dt}}{E}=3.02\times10^{-11}

Hence, The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

5 0
3 years ago
Gene therapy is a form of <br> .
stira [4]

Answer:

Gene therapy is an experimental form of treatment that uses gene transfer of genetic material into the cell of a patient to cure the disease. The idea is to modify the genetic information of the cell of the patient that is responsible for a disease, and then return that cell to normal conditions.

Explanation:

3 0
3 years ago
Read 2 more answers
Car A (1750 kg) is travelling due south and car B (1450 kg) is travelling due east. They reach the same intersection at the same
Contact [7]

Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as

\underset{V_{A}}{\rightarrow} = velocity of car A before collision = 0 i - V_{A} j

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M_{A} = mass of car A = 1750 kg

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Using conservation of momentum

M_{A}  \underset{V_{A}}{\rightarrow} + M_{B}  \underset{V_{B}}{\rightarrow} = (M_{A} + M_{B}) ( \underset{V_{AB}}{\rightarrow} )

(1750) (0 i - V_{A} j) + (1450) (V_{B} i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)

(1450) V_{B} i - (1750) V_{A} j = 97600 i - 60160 j

Comparing the coefficient of "i" and "j" both side

(1450) V_{B} = 97600    and - (1750) V_{A} = - 60160

V_{B} = 67.3 km/h        and  V_{A} = 34.4 km/



6 0
4 years ago
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