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Sedbober [7]
2 years ago
14

HELP MAY I WILL GIVE U BRAINLIEST JUST PLEEZSE HELP WJKJNIURWNHF

Physics
2 answers:
luda_lava [24]2 years ago
8 0
Object at rest: an object that has zero velocity (does not move)

Object in motion: an object moving by am unbalanced force

hope this helped:)
kozerog [31]2 years ago
7 0

Answer:

A object in rest is an object that is not moving or a object that is not moving. A object in motion is a object that is in motion or moving.

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Magnetism Assessment
musickatia [10]

Answer:

greater from magnet B to A

6 0
3 years ago
The weight of a body above sea level varies inversely with the square of the distance from the center of Earth. If a woman weigh
Serjik [45]

Answer:

89.16pounds

Explanation:

The equation that defines this problem is as follows

W=k/X^2

where

W=Weight

K= proportionality constant

X=distance from the center of Earth

first we must find the constant of proportionality, with the first part of the problem

k=WX^2=131x3960^2=2054289600pounds x miles^2

then we use the equation to calculate the woman's weight with the new distance

W=2054289600/(4800)^2=89.16pounds

4 0
3 years ago
a motorcycle starting from rest has an acceleration of 2.6m/s how long does it take the motorcycle to travel a distance of 120
Setler79 [48]
46.15 seconds to reach 120
5 0
4 years ago
Can someone help me with one through seven I will mark you the brainly
ki77a [65]

Answer:

1.  F = M x A

2. Force  

3. 2nd Law: Force

4. a, b, c (in order)

5. 3rd Law: Action and Reaction

6. b, c, a (in order)

7. 1st Law: Inertia

3 0
3 years ago
Read 2 more answers
The magnetic field due to a utility wire is 0.10 mT when you are at a distance of 10 meters from it. What current (in Amperes) f
ale4655 [162]

Answer:

I = 5000 A

Explanation:

We will use Ampere's Law to calculate the current:

B = \frac{\mu I}{2\pi r}\\\\

where,

B = Magnetic Field Strength = 0.1 mT = 1 x 10⁻⁴ T

μ = Permeability of Free Space = 4π x 10⁻⁷ N/A²

I = Current = ?

r = radius = 10 m

Therefore,

1\ x\ 10^{-4}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(I)}{2\pi(10\ m)}\\\\I = \frac{(1\ x\ 10^{-4}\ T)(2\pi (10\ m))}{4\pi\ x\ 10^{-7}\ N/A^2}

<u>I = 5000 A</u>

4 0
3 years ago
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