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slamgirl [31]
2 years ago
9

Technician A states that the SRS systems help to provide a level of accident avoidance. Technician B states that the SRS system

helps to cushion the passengers in case of an accident. Who is correct?
Engineering
1 answer:
Veseljchak [2.6K]2 years ago
4 0

The <em>supplemental restraint system</em> is automatically deployed in cases of collison on other increase passenger safety. Hence, Technician B is right.

  • The supplement restraint system is a presssure filled airbag which automatically inflates and slowly deflates whenever there is a collision worthy of deployment.

  • These cushions the effect of the collison on the passenger as it acts as barrier between the passenger and the object which the passenger's body could hit during collison.

Therefore, the SRS acts to cushion the effect of injuries during accident and does not prevent accident.

Learn more :brainly.com/question/1378025

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What is the effect of the workpiece specific cutting energy on the cutting forces, and why?
ella [17]

Explanation:

Specific cutting energy:

   It the ratio of power required to cut the material to metal removal rate of material.If we take the force required to cut the material is F and velocity of cutting tool is V then cutting power will be the product of force and the cutting tool velocity.

Power P = F x V

Lets take the metal removal rate =MRR

Then the specific energy will be

    sp=\dfrac{F\times V}{MRR}

If we consider that metal removal rate and cutting tool velocity is constant then when we increases the cutting force then specific energy will also increase.

8 0
4 years ago
The yield strength of mild steel is 150 MPa for an average grain diameter of 0.038 mm ; yield strength is 250 MPa for average gr
djyliett [7]

Answer:

Explanation:

Hall-Petch equation provides direct relations between the strength of the material and the grain size:

σ=σ0+k/√d , where d- grain size, σ- strength for the given gran size, σ0 and k are the equation constants.

As in this problem, we don't know the constants of the equation, but we know two properties of the material, we are able to find them from the system of equations:

σ1=σ0+k/√d1

σ2=σ0+k/√d2 , where 1 and 2 represent 150MPa and 250MPa strength of the steel.

Note, that for the given problem, there is no need to convert units to SI, as constants can have any units, which are convenient for us.

From the system of equations calculations, we can find constant: σ0=55.196 MPa, k=18.48 MPa*mm^(0.5)

Now we are able to calculate strength for the grain diameter of 0.004 mm:

σ=55.196+18.48/(√0.004)=347.39 MPa

The strength of the steel with the grais size of 0.004 mm is 347.39 MPa.

6 0
4 years ago
1. Asbestos can be dangerous but is not a known carcinogen.<br> A) O True<br> B) O False
Leya [2.2K]
I believe it’s A. True
4 0
3 years ago
Harmony in music is characterized by _____.
stira [4]

Answer:

the vertical relationship of pitches.

Explanation:

Harmony can be defined as the use of simultaneous pitches ( two or more tones and notes) or chords played at the same time together.

Harmony in music is characterized by the vertical relationship of pitches. The three most popular and essential forms of harmony are;

1. Diatonic harmony.

2. Non-diatonic harmony.

3. Atonal harmony.

6 0
3 years ago
Read 2 more answers
Fix the code so the program will run correctly for MAXCHEESE values of 0 to 20 (inclusive). Note that the value of MAXCHEESE is
GarryVolchara [31]

Answer:

Code fixed below using Java

Explanation:

<u>Error.java </u>

import java.util.Random;

public class Error {

   public static void main(String[] args) {

       final int MAXCHEESE = 10;

       String[] names = new String[MAXCHEESE];

       double[] prices = new double[MAXCHEESE];

       double[] amounts = new double[MAXCHEESE];

       // Three Special Cheeses

       names[0] = "Humboldt Fog";

       prices[0] = 25.00;

       names[1] = "Red Hawk";

       prices[1] = 40.50;

       names[2] = "Teleme";

       prices[2] = 17.25;

       System.out.println("We sell " + MAXCHEESE + " kind of Cheese:");

       System.out.println(names[0] + ": $" + prices[0] + " per pound");

       System.out.println(names[1] + ": $" + prices[1] + " per pound");

       System.out.println(names[2] + ": $" + prices[2] + " per pound");

       Random ranGen = new Random(100);

       // error at initialising i

       // i should be from 0 to MAXCHEESE value

       for (int i = 0; i < MAXCHEESE; i++) {

           names[i] = "Cheese Type " + (char) ('A' + i);

           prices[i] = ranGen.nextInt(1000) / 100.0;

           amounts[i] = 0;

           System.out.println(names[i] + ": $" + prices[i] + " per pound");

       }        

   }

}

7 0
4 years ago
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