Ask question

Ask question

All categories

2 years ago

7

haun wants to enter the science fair at his school. he has a list of ideas for his project. which questions could be answered th

rough scientific investigations. check all that apply

1 answer:

Allisa [31]2 years ago

6 0

Correct Answer:

- Does pressure have an effect on the volume of a gas?

- Which brand of soap is the best for cleaning grease off dishes?

You might be interested in

A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-

djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

$\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}$

$\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}$

$\frac{3-y}{y}=\sqrt{\frac{7}{2}}$

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0

3 years ago

Help plssssssssssss

grin007 [14]

C. A little backward, 100 or 110 degrees

6 0

3 years ago

A photon of wavelength 192 nm strikes an aluminum surface along a line perpendicular to the surface and releases a photoelectron

alex41 [277]

Answer:

$KE=3.529\times10^{−27}\ J$

Explanation:

Given that

Wavelength λ=192 nm

So energy of photon,E

$E=\dfrac{hC}{\lambda }$

Now by putting the values

$h=6.6\times 10^{-34}\ m^2.kg/s$

$C=3\times 10^{8}\ m/s$

$E=\dfrac{6.6\times 10^{-34}\times 3\times 10^{8}}{192\times 10^{-9} }$

$E=1.03\times 10^{-18} J$

We know that

Kinetic energy given as

$KE=\dfrac{P^2}{2m}$

$KE=\dfrac{E^2}{2mC^2}$

$KE=\dfrac{(1.03\times 10^{-18})^2}{2\times 1.67\times 10^{-27}(3\times 10^8)^2}$

$KE=3.529\times10^{−27}\ J$

5 0

3 years ago

A 5 μF capacitor is connected to a 12 V battery. The charge on each plate of the capacitor is:

ziro4ka [17]

1 farad = 1 coulomb/volt

5 μF = 5 x 10⁻⁶ coulomb/volt

= 60 x 10⁻⁶ coulomb / 12 volts

The charge is 60 x 10⁻⁶ coulombs = 6 x 10⁻⁵ (choice-A)

3 0

3 years ago

A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes.

Jobisdone [24]

Answer:

F=507.7N

Explanation:

According to Newton's second law:

$\sum F=m.a$

in this case, the football players need to drag the coach at a constant velocity, thus means with no acceleration, so:

$\sum F=0\\\\-F_f+F_p*cos(\theta)=0\\\\$

there are 20 degrees between the two ropes that means each player exerts a force 10 degrees from the zero reference.

$F_p=2*F\\\\F=\frac{1000N}{2*cos(10)}\\\\F=507.7N$

5 0

3 years ago